正则表达式捕获不包含字符串并以扩展名结尾的文本 [英] Regex to catch text not containing a string and ending with an extension

问题描述

我正在尝试使用 2 个正则表达式，一个包含关键"并以(s)css"结尾的捕获字符串，第二个用于不包含关键"的字符串(具有相同的扩展规则).

I'm trying to have 2 regex, one catching string containing 'critrical' and ending with '(s)css' and second one for string which don't contain 'critical' (with the same extentions rule).

我已经有了第一个，它是 /.*?critical.*\.s?css$/

I already have the first one and it is /.*?critical.*\.s?css$/

但我无法制作第二个.我认为它会像 /.*?(?<!\.critical).*\.s?css$/ 一样简单.但是，似乎没那么容易，因为它不起作用......

But I can't manage to make the second one. I thought it would be as easy as /.*?(?<!\.critical).*\.s?css$/. But, seems it's not that easy as it doesn't work...

推荐答案

试试这个正则表达式(对于不包含关键词，最后包含 css 的字符串):

Try this regex(for the string not containing the word critical and containing css in the end):

^(?!.*critical).*s?css$

点击演示

说明:

• ^ - 断言字符串的开始
• (?!.*critical) - negative lookahead 验证字词 critical 不存在于字符串中
• .* - 匹配 0+ 次(贪婪地)除新行之外的任何字符
• s?css - 匹配可选的 s 后跟 css
• $ - 断言字符串的结尾

• ^ - asserts the start of the string
• (?!.*critical) - negative lookahead to validate that the word critical is not present in the string
• .* - matches 0+ occurrences(greedily) of any character except a new line
• s?css - matches an optional s followed by css
• $ - asserts the end of the string

并且，对于包含单词critical和最后包含css的字符串，您可以尝试:

And, for the string containing the word critical and containing css in the end, you can try:

^(?=.*critical).*s?css$

点击演示

这个正则表达式的唯一区别是它使用正向前瞻来确保字符串critical存在于字符串中的某处.

The only difference with this regex is that it uses a Positive lookahead to make sure that the string critical exist somewhere in the string.

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