BackgroundUploader 示例在使用 PHP 的 Apache 服务器上不起作用 [英] BackgroundUploader Sample does not work on Apache Server with PHP

问题描述

我必须从 Windows Phone 8.1 应用程序上传视频文件.我正在使用 BackgroundTrasfer 示例，但用于服务器端只是一个aspx脚本.但我需要 PHP.

I have to upload a video file from an windows phone 8.1 app. I am using the BackgroundTrasfer sample but for the server side there is just a aspx script. But I need PHP.

我找到了这个 PHP 脚本

I have found this PHP script

<?php  
    $target = "upload/";  
    $target = $target . basename( $_FILES['Filename']['name']) ;  
    $ok=1;  

    if(move_uploaded_file($_FILES['Filename']['tmp_name'], $target))  { 
        echo "The file ". basename( $_FILES['Filename']['name']). " has been uploaded"; 
    }  else { 
        echo "Sorry, there was a problem uploading your file."; 
    } 
?> 

最后我得到 200 并且没有错误，但是服务器上没有文件，所以我会说服务器部分有问题吗?在哪里可以获得工作服务器部分脚本?

Finally I get a 200 and no errors but there is no file on the server so I would say the server part is the problem? Where I can get a working server part script?

附言目录upload"与upload.php存在于同一目录下，权限为777.

P.S. The directory "upload" exist in the same directory like the upload.php and has the rights 777.

推荐答案

你需要做一个 multipart/form-data 请求.

You need to do a multipart/form-data request.

尝试类似(伪代码):

List<BackgroundTransferContentPart> parts =
    new List<BackgroundTransferContentPart>();
var part = new BackgroundTransferContentPart("myFile");
part.SetFile(file);
parts.Add(part);

UploadOperation upload = await uploader.CreateUploadAsync(
    uri,
    parts);

var task = upload.StartAsycn().AsTask();

在 PHP 上，使用 print_r($_FILES) 浏览接收到的文件.

On PHP, explore the recevied files with print_r($_FILES).

这篇关于BackgroundUploader 示例在使用 PHP 的 Apache 服务器上不起作用的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！