在 C++ 中，如何在第一个结束后才执行第二个“system()"? [英] In C ++, how to execute the second 'system()' only after the first one is over?

问题描述

请看下面的代码.如果有任何替代系统可以满足我的要求，那也很好.

See the code below. If there is any alternative to system that does what I want it would be good too.

strcat(comando1,"start c:\\arquiv~1\\winrar\\rar a D:\\sisbibbkp\\teste1");
strcat(comando1,data);
strcat(comando1,".rar E:\\softwares");
system(comando1);

strcat(comando2,"start c:\\arquiv~1\\winrar\\rar a D:\\sisbibbkp\\teste2");
strcat(comando2,data);
strcat(comando2,".rar E:\\softwares");
system(comando2);  // I want this system to run only after system (command1) finishes.

推荐答案

start 命令将事物作为单独的作业运行:

The start command runs things as a separate job:

C:\Users\Pax> start /?
Starts a separate window to run a specified program or command.

如果您想等待它完成，只需从命令中删除 start.

If you want to wait for it to finish, just remove the start from the command.

或者，如果您希望整个 thing 单独运行但让第 2 步等待第 1 步完成，请将两者都放入 cmd 脚本(不带 start bits) 和 start cmd.exe 在您的脚本上执行此操作.

Or if you want the whole thing to run separately but have step 2 wait for step 1 to finish, put both into a cmd script (without the start bits) and start cmd.exe on your script to do it.

这应该启动一个单独的作业来运行脚本，但该作业将按顺序运行脚本中的命令.

That should start a separate job to run the script but that job will run the command in the script sequentially.

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