计算 Mathematica 中每组的磁头数 [英] Count the number of heads per set in Mathematica

问题描述

首先感谢大家的回复.我正在尽我最大的努力跟上所有的建议.但是我正在努力保持正轨.

First of all, thank you for all your responces. I am doing my best to keep up with all the suggestions. However I'm trying to stay on track.

所以现在我有

s = Table[RandomChoice[{Heads, Tails}, 2 i + 1], {i, 10}];

接下来，我想计算每个i"出现的Heads"的数量.

Next, I want to count the number of "Heads" that occur for each "i".

我可以为一个案例做到这一点....说 5，

I can do this for one case....say 5,

n = RandomChoice[{Heads, Tails}, 5];
n1 = Count[n, Heads];

但是我无法扩展它....

But I am having trouble expanding this....

再次感谢.

附言什么是投反对票?太简单了?

p.s. what are down votes? Too easy?

推荐答案

Map (/@) 统计列表中人头数的功能:

Map (/@) the function of counting heads in a list:

Count[#, Heads]&

到s中的每个子列表.因此:

to each sublist in s. Hence:

Count[#, Heads]& /@ s

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