有没有办法将这个PHP放入数组并简化它? [英] Is there a way to put this PHP into an array and simplify it?

问题描述

以下代码加载在指定文件夹(单独定义)中找到的所有 .php 文件.有没有办法把这个放到数组中来简化代码?

The following code loads all .php files found in the specified folder (defined separately). Is there a way to put this into an array to simplify the code?

只有几个变量发生了变化，但基本上代码重复了几次.

Only a couple of variables change but essentially the code repeats several times.

// The General Files

$the_general = opendir(FRAMEWORK_GENERAL);

while (($the_general_files = readdir($the_general)) !== false) {
    if(strpos($the_general_files,'.php')) {
        include_once(FRAMEWORK_GENERAL . $the_general_files);       
    }       
}

closedir($the_general);


// The Plugin Files

$the_plugins = opendir(FRAMEWORK_PLUGINS);

while (($the_plugins_files = readdir($the_plugins)) !== false) {
    if(strpos($the_plugins_files,'.php')) {
        include_once(FRAMEWORK_PLUGINS . $the_plugins_files);       
    }       
}

closedir($the_plugins);

还有几个部分调用不同的文件夹.

There are several more sections which call different folders.

非常感谢任何帮助.

干杯，詹姆斯

推荐答案

我更好的方法是使用 glob().并把它变成一个函数.

I nicer way to do this would to use glob(). And make it into a function.

function includeAllInDirectory($directory)
{
    if (!is_dir($directory)) {
        return false;
    }

    // Make sure to add a trailing slash
    $directory = rtrim($directory, '/\\') . '/';

    foreach (glob("{$directory}*.php") as $filename) {
        require_once($directory . $filename);
    }

    return true;
}

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