多个 preg_replace RegEx 用于不同的 URL [英] Multiple preg_replace RegEx for different URLs

问题描述

我有一个这样的字符串:

I have a string like this:

Blablabla http://www.soundcloud.com/artist/track
www.facebook.com/page is my page
Try www.youtube.com/watch?v=1234567 for my video
Check http://www.somesite.com/bla.

我想替换 URL 并在用户生成的帖子中插入不同的 wordpress 短代码，自动与视频或 soundcloud 小部件交换 url，并从所有其他 URL 和电子邮件创建常规链接到这样的东西(简化):

I would like to replace URLs and insert different wordpress shortcodes inside a user generated post, exchange urls with videos or soundcloud widgets automatically and create regular links from all the other URLs and emails into something like this (simplified):

Blablabla [soundcloud]www.soundcloud.com/artist/track[/soundcloud]
[facebook]www.facebook.com/page[/facebook] is my page
Try [youtube]www.youtube.com/watch?v=1234567[/youtube] for my video
Check [url]www.somesite.com/bla[/url].

所以我想我需要对字符串运行几个 preg_replace 操作.

So I think I need to run several preg_replace actions on the string.

在我用 Wordpress 短代码替换 Soundcloud、Facebook 和 Youtube URL 后，我需要在剩余的 URL 上运行 preg_replace，例如 http://www.somesite.com/bla 但由于 Facebook/Soundcloud/Youtube 模式在字符串中仍然可用(现在在短代码中)，它们将再次被替换为...

After I replaced Soundcloud, Facebook and Youtube URLs with the Wordpress shortcodes I need to run a preg_replace on the remaining URLs like http://www.somesite.com/bla but since the Facebook/Soundcloud/Youtube patterns are still available in the string (now inside the shortcodes) they will be replaced again into...

[youtube][url]www.youtube.com/watch?v=1234567[/url][/youtube]

我不想要这种行为.我应该是这样的:

I do not want this behaviour. I should be like this:

[url]www.youtube.com/watch?v=1234567[/url]

这是我的基本正则表达式:

This is my basic RegEx:

((https?://)(www.)|(https?://)|(www.))[^ <]+

((https?://)(www.)|(https?://)|(www.))[^ <]+

我需要替换以 http、https 和 www 开头的 URL

I need to replace URLs beginning with http, https and www

有人解决了吗?

问候，

垫子

推荐答案

我建议您查看 preg_replace_callback 函数代替.

I'd recommend you look into the preg_replace_callback function instead.

与其尝试匹配不同的 url 子集，对于每个不同的站点，只需将它们全部匹配即可！然后，在代码中检查特定的捕获组以检查 url 的基础

Rather than trying to match different subsets of urls, for each different site, just match them all! Then, in code check a specific capturing group to check the base of the url

因此，在 php 代码中，如果 url 以 facebook 开头，则将 url 替换为 facebook 短代码，依此类推.

So, in php code, if the url starts with facebook, replace the url with the facebook shortcode, and so on.

这是您的正则表达式，稍作修改以捕获域.记住要逃避你的字面意思.这只会捕获域的第一个 < / ? 或空格，然后直到第一个 < 或 URL 其余部分的空格.如果您发现任何不适用于此方法，则可能需要对其进行修改.

Here's your regex, slighly modified to capture the domain. Remember to escape your literal periods. This just captures up to the first < / ? or whitespace for the domain, then until the first < or whitespace for the rest of the URL. You might have to modify this if you find anything that this doesn't work for.

((https?://)(www\.)|(https?://)|(www\.))([^</\?\s]+)[^<\s]*

现在是一些 php 代码.回想一下 $matches[0] 将具有完整匹配，而 $matches[6] 将具有第 6 个捕获组 - 在这种情况下 ([^</\?\s]+),域部分

And now some php code. Recall that $matches[0] will have the full match, and $matches[6] will have the 6th caputuring group - in this case ([^</\?\s]+), the domain part

$post = preg_replace_callback(
    '/((https?:\/\/)(www\.)|(https?:\/\/)|(www\.))([^<\/\?\s]+)[^<\s]*/',
    function ($matches) {
        switch($matches[6]){
            case 'facebook.com':
                return "[facebook]" . $matches[0] . "[/facebook]";

            case 'youtube.com':
                return "[youtube]" . $matches[0] . "[/youtube]";

            case 'soundcloud.com':
                return "[soundcloud]" . $matches[0] . "[/soundcloud]";

            default:
                return "[url]" . $matches[0] . "[/url]";
        }
    },
    $post);

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