你如何在 Swift 3.x 中使用 Storyboards/Cocoa 引用视图的窗口 [英] How do you reference the view's window in Swift 3.x using Storyboards/Cocoa

问题描述

随着 Xcode 和 Swift 的所有变化，我无法弄清楚如何在使用 XIB 的项目中处理 stotyboard 驱动的项目中的视图窗口.macOS 编程新手，如果这是基本内容，请提前道歉:

with all the changes in Xcode and Swift, I can't figure out how to address the view's window in a stotyboard-driven project in the way I'm doing it in projects using XIBs. New to macOS programming so apologies in advance if this is basic stuff:

使用情节提要时，我如何更改视图的窗口状态，例如:

When using a storyboard, how do I change the view's window state using for instance:

window.titleVisibility = .hidden
window.setContentSize(size)

在一个 xib 驱动的项目中，我使用

In an xib-driven project, I'm using

@IBOutlet weak var window: NSWindow!

但这似乎与故事板的工作方式不同.我如何使用故事板做同样的事情?任何帮助表示赞赏！

but this doesn't seem to work the same way with storyboards. How do I do the same tihing using storyboards? Any help appreciated!

推荐答案

您可以通过访问其 window 属性来获取视图窗口的引用.请注意，它不能在 view did load 内完成，但您可以使用延迟初始化程序为您的视图控制器创建一个窗口属性:

You can get a reference of your view window accessing its window property. Note that it can not be done inside view did load but you can create a window property for your view controller using a lazy initializer:

lazy var window: NSWindow! = self.view.window

并且您可以在方法 viewWillAppear 中进行窗口自定义:

And you can do your window customization inside the method viewWillAppear:

import Cocoa


class ViewController: NSViewController {

    lazy var window: NSWindow! = self.view.window

    override func viewWillAppear() {
        super.viewWillAppear()
        window.titleVisibility = .hidden
    }
}

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