使用 PHP 从 XML 中的节点内部获取数据 [英] Getting Data from inside a node in XMl with PHP

问题描述

所以我不确定我需要什么或如何真正描述我需要什么，但希望有人能理解.

整个xml文件的单个元素如下所示:

<前>for ( $counter = 1; $counter load($file_xml);//确保路径正确$note = $objDOM->getElementsByTagName("事件");//遍历 XML 提要$i = 0;foreach( $note as $value ){$event_id = $value->getAttribute('ID');# 场地标识$VenueID = $value->getElementsByTagName("Venue");$venue_id = $VenueID->item(0)->getAttribute("ID");}}

arrgggg 它并没有真正完全复制他的代码.天啊.

顶部是for循环的迭代.在 foreach 语句中，我有插入语句；这是我尝试插入图像 URL 的地方

<事件名称>事件名称</事件名称><艺术家><艺术家姓名>艺术家姓名</艺术家姓名></艺术家><场地 ID="IDIDIDID"><场地名称>场地名称</场地名称><图像><Url>IMAGE_URL</Url><宽度>205</宽度><高度>115</高度></图片></场地></事件>

我能够获得所需的其余图像，但图像 URL 除外.我试图将它分解为一个数组并获得第一个值，但这没有用.我在这里看到了另一篇文章并尝试使用 preg_match 但这没有用.有谁知道我该怎么做:

获取单个事件"行内图像的 URL?

这是我所拥有的开始:

$Image = $value->getElementsByTagName("Image");$venue_img_2 = $Image->item(1)->nodeValue;

这将返回 IMAGE_URL 205 115

注意:IMAGE_URL 与 205 和 115 之间的空格"实际上并不是空格"

提前致谢.

解决方案

假设你的 Event 节点有一个父节点(即 ......</Event></Events>):

$xml = simplexml_load_file($file_xml);foreach($xml->Event as $event) {$idAttr = 'ID';$event_id = (string) $event->attributes()->$idAttr;$venue_id = (string) $event->Venue->attributes()->$idAttr;$venue_img_2 = (string) $event->Venue->Image->Url;}

So im not sure what or how to really describe what i need but hopefully someone will understand.

single element of the total xml file looks like this:

for ( $counter = 1; $counter load($file_xml); //make sure path is correct
  $note = $objDOM->getElementsByTagName("Event");

  // Loop through XML feed
  $i = 0;
  foreach( $note as $value )
  {
    $event_id       = $value->getAttribute('ID');
    # venue id
    $VenueID        = $value->getElementsByTagName("Venue");
    $venue_id       = $VenueID->item(0)->getAttribute("ID");
  }
}

arrgggg its not really copying he code exactly. geez.

the top is the iteration of the for loop. inside the foreach statement I have the insert statement; which is where I am trying to insert the image URL

<Event ID="IDIDIDIDID">
   <EventName>EVENT NAME</EventName>
   <Artist>
      <ArtistName>ARTIST NAME</ArtistName>
   </Artist>

   <Venue ID="IDIDIDID">
    <VenueName>VENUE NAME</VenueName>
       <Image>
           <Url>IMAGE_URL</Url>
           <Width>205</Width>
           <Height>115</Height>
        </Image>
      </Venue>
 </Event>

I am able to get the rest of the imageofmation I need, except for the image URL. i have tried to break it up as an array and get the first value but that didnt work. I saw another post here and tried to use preg_match but that didnt work. does anyone know how i could:

get the URL of the image inside the individual "Event" row?

this is the beginning of what I have:

$Image          = $value->getElementsByTagName("Image");
$venue_img_2    = $Image->item(1)->nodeValue;

this will return IMAGE_URL 205 115

Note: the "space" between the IMAGE_URL and 205 and 115 doesn't seem to actually be a "space"

thanks in advance.

解决方案

Assuming your Event nodes have one parent (ie <Events><Event>...</Event><Event>...</Event></Events>):

$xml = simplexml_load_file($file_xml);

foreach($xml->Event as $event) {
    $idAttr = 'ID';

    $event_id = (string) $event->attributes()->$idAttr;
    $venue_id = (string) $event->Venue->attributes()->$idAttr;

    $venue_img_2 = (string) $event->Venue->Image->Url;
}

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