XSLT 转换为 xml，按键分组 [英] XSLT transformation to xml, grouping by key

问题描述

我在编写 xsl 以将我的 xml 转换为 raport 版本时遇到问题.看起来像这样:

I have problem with write xsl to transform my xml to raport version. It looks like that:

<library>
    <authors>
        <author id="1001">John</author>
        <author id="1002">Tom</author>
    </authors>
    <articles>
        <article>
            <authorId>1001</authorId>
            <title>Article1</title>
        </article>
        <article>
            <authorId>1002</authorId>
            <title>Article2</title>
        </article>
        <article>
            <authorId>1001</authorId>
            <title>Article3</title>
        </article>
    </articles>
</library>

我想将其转换为:

<raport>
    <authorArticles>
        <author>John</author>
        <articles>
            <article>Article1</article>
            <article>Article3</article>
        </articles>
    </authorArticles>
    <authorArticles>
        <author>Tom</author>
        <articles>
            <article>Article2</article>
        </articles>
    </authorArticles>
</raport>

我有想法为每个人使用，用于作者的 id 和文章的嵌套，但我不知道该怎么做.有人知道如何进行这种转换吗?

I have idea to use for each, on for ids in authors and neasted for articles, but I dont know how to do it. Anyone know how to make this transformation ?

推荐答案

这个 XSLT:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>

<xsl:template match="node() | @*" name="identity">   
    <xsl:copy>
        <xsl:apply-templates select="node() | @*"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="library">
    <raport>
        <xsl:apply-templates select="authors/author"/>
    </raport>
</xsl:template>

<xsl:template match="author">
    <authorArticles>
        <xsl:call-template name="identity"/>
        <articles>
            <xsl:apply-templates select="../../articles/article[authorId = current()/@id]"/>
        </articles>
    </authorArticles>
</xsl:template>

<xsl:template match="article">
    <xsl:call-template name="identity"/> <!-- In case of more characteristics -->
</xsl:template>

<xsl:template match="title">
    <xsl:value-of select="."/>
</xsl:template>

<xsl:template match="author/@id | authorId"/>

</xsl:stylesheet>

使用此 XML 输入:

With this XML input:

<library>
<authors>
    <author id="1001">John</author>
    <author id="1002">Tom</author>
</authors>
<articles>
    <article>
        <authorId>1001</authorId>
        <title>Article1</title>
    </article>
    <article>
        <authorId>1002</authorId>
        <title>Article2</title>
    </article>
    <article>
        <authorId>1001</authorId>
        <title>Article3</title>
    </article>
</articles>
</library>

提供所需的结果:

<raport>
    <authorArticles>
       <author>John</author>
       <articles>
          <article>Article1</article>
          <article>Article3</article>
       </articles>
    </authorArticles>
    <authorArticles>
       <author>Tom</author>
       <articles>
           <article>Article2</article>
       </articles>
    </authorArticles>
</raport>

进一步的优化可能是使用键，但你的结构看起来还为时过早.

The further optimization might be using keys, but it looks premature with your structure.

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