如何在 MSXML6 上获得等效的 max()? [英] How to get equivalent of max() on MSXML6?

问题描述

显然 MSXML6 不支持 XSLT 2.0，至少不支持 max() 函数.我需要找出其兄弟节点中包含最高值的节点.它们的顺序是任意的.

Evidently MSXML6 doesn't support XSLT 2.0, at least not the max() function. I need to find out the node that contains the highest value among its siblings. They are in arbitrary order.

我希望订单保持相同，因此添加 order-by 和检查 [0] 是不可能的.

I want the order to remain identical so adding order-by and checking [0] is out of question.

我想用一个 XPath 语句来做到这一点.我不想调用模板或涉及任何比这更复杂的逻辑.我确信某处嵌入了一个可怕的 MS Scripting Extensions.呃.

I want to do this with a single XPath statement. I don't want to call templates or involve any more complex logic than that. I'm sure there is a horrifying MS Scripting Extensions embedded somewhere. Eww.

我想到了:

elem1[count(../elem1[@value < current()/@value]) = 0]

但它没有像我预期的那样工作(总是返回第一个节点).你还能想到其他任何漂亮的 XPath 魔法吗?

But it didn't work as I expected (returns the first node always). Any other nifty XPath magic can you think of there?

推荐答案

尝试

elem1[not(../elem1/@value > @value)]

也就是说，您需要 elem1，对于 not 另一个 elem1 具有更大的 @value.

That is, you want the elem1 for which it is not the case that another elem1 has a greater @value.

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