解析谷歌日历 XML 提要 [英] Parsing google calendar XML feed
本文介绍了解析谷歌日历 XML 提要的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有来自公共谷歌日历的 XML 提要.看起来像这样:
I've got XML feed from public google calendar. Looks like this:
<?xml version='1.0' encoding='UTF-8'?>
<feed xmlns='................' xmlns:gd='http://schemas.google.com/g/2005'>
<id>http://www.google.com/calendar/feeds/........./public/full</id>
<updated>2009-08-24T10:57:00.000Z</updated>
<category scheme='http://schemas.google.com/g/2005#kind' term='http://schemas.google.com/g/2005#event'/>
<title type='text'>Sports Events</title>
.....
<entry>
<id>...........</id>
<published>2009-08-14T00:29:58.000Z</published>
<updated>2009-08-14T00:29:58.000Z</updated>
<category scheme='http://schemas.google.com/g/2005#kind' term='http://schemas.google.com/g/2005#event'/>
..............
<georss:where>
<gml:Point>
<gml:pos>11.111111 -22.22222</gml:pos>
</gml:Point>
</georss:where>
<gd:eventStatus value='http://schemas.google.com/g/2005#event.confirmed'/>
<gd:transparency value='http://schemas.google.com/g/2005#event.transparent'/>
<gCal:uid value='.........@google.com'/>
<gCal:sequence value='0'/>
<gd:when startTime='2009-10-03' endTime='2009-10-04'/>
.............
现在到 PHP:
$calendar = simplexml_load_file('http://my.feed.com');
foreach ($calendar->entry as $item) {
//here I get the whole <entry> node
$gd = $item->children('http://schemas.google.com/g/2005');
// now in $gd I have all nodes like <gd:XXXXX>
}
问题是如何从这里获取价值?
The problem is how to get value from here?
<gml:pos>11.111111 -22.22222</gml:pos>
它不存在于我的 $gd 变量中,如何获取此节点?
Its not present in my $gd variable, how to get this node?
推荐答案
我强烈推荐使用这个库:https://github.com/collegeman/coreylib.它会让一切从头到尾都变得容易得让人麻木.
I highly recommend using this library: https://github.com/collegeman/coreylib. It'll make everything from start to finish mind-numbingly easy.
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