检查 XML 元素是否等于另一个 XML 元素，忽略空值 [英] Check if XML element equals another XML element, ignoring empty values

问题描述

我正在检查字符串给出的两个 XML 元素是否与此方法相等:

I'm checking if two XML elements given by string are equal with this method:

private static bool XmlEquals(string s1, string s2)
{
    return XNode.DeepEquals(XElement.Parse(s1), XElement.Parse(s2));
}

除非其中一个元素有开始和结束标签，而另一个有这样的结束标签，否则这项工作是可行的:

This work unless one of the elements has opening and closing tags and the other has a closed tag like this:

<MyElement SomeAttribute="some value" />
<MyElement SomeAttribute="some value"></MyElement>

我能否以某种方式比较两个 XML 元素，使上述情况被认为相等?

Can I somehow compare two XML elements in a way, that the above case is considered equal?

推荐答案

解决这个特定问题的直接方法是 明确引入右括号:

Straightforward way to solve this particular problem is to introduce closing brackets explicitly:

 private static bool XmlEquals(string s1, string s2)
 {
      var firstElement = XElement.Parse(s1);
      var secondElement = XElement.Parse(s2);
      IntroduceClosingBracket(firstElement);
      IntroduceClosingBracket(secondElement);

      return XNode.DeepEquals(firstElement, secondElement);
 }

 private static void IntroduceClosingBracket(XElement element)
 {
      foreach (var descendant in element.DescendantsAndSelf())
      {
           if (descendant.IsEmpty)
           {
                descendant.SetValue(String.Empty);
           }
      }
 }

不过，遍历所有后代可能会导致性能下降.

Loop through all descendants may cause a performance hit, though.

这篇关于检查 XML 元素是否等于另一个 XML 元素，忽略空值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！