XPath:获取元素类型 [英] XPath: get element type

问题描述

这是一个 XPath 查询，它将打印文件中每个元素的完整路径

This is an XPath query which would print full path of every element in the file

for $boy in //*
return string-join(($boy/ancestor-or-self::*/name()), "::")

我如何获得元素的类型(我首先需要知道原始类型:xs:integer、xs:string 等)?

How do I get the element's type as well (I need to know primitive types foremost: xs:integer, xs:string, etc)?

推荐答案

没有确定元素类型的函数.当您使用 flwor 表达式时，我猜您的 XPath 处理器支持 XPath 2.0:然后您可以使用 instance of 来确定类型，例如.

There is no function to determine an element's type. As you're using flwor expressions, I guess your XPath processor supports XPath 2.0: then you can use instance of to determine the type, eg.

• xs:string 的foo"实例
• 1 个 xs:integer 实例
• ///* element()的实例*

您可以使用 if/else-chain 来确定类型(该示例使用 XQuery，在 XPath 中您不能定义函数)，但我现在无法真正想出一个 XPath 应用程序示例.

You could use use an if/else-chain to determine the type (the example uses XQuery, in XPath you cannot define functions), but I cannot really come up with an XPath application example right now.

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