XPath 获取父元素 [英] XPath get parent element

问题描述

我有一个与 XPath 相关的问题.我有一个像这样的 XML 条目列表:

I have an XPath related question. I have a list of XML entries like this:

<NavigationEntry>
<BaseData>
    <Name>Entry Name</Name>
  </BaseData>
  <Relation>
    <RelationEntry isDefault="0">
      <ParentNavigationEntry>456</ParentNavigationEntry>
      <Order>200</Order>
    </RelationEntry>
  </Relation>

<NavigationEntry>
  <BaseData>
    <Name>Entry Name</Name>
  </BaseData>
  <Relation>
    <RelationEntry isDefault="0">
      <ParentNavigationEntry>123</ParentNavigationEntry>
      <Order>200</Order>
    </RelationEntry>
  </Relation>

问题是:如何获取所有具有值为 456 的 Field ParentNavigationEntry 的导航条目.

The question is: how do I get all navigation entries that has a Field ParentNavigationEntry with the value 456.

我试过了//NavigationEntry//RelationEntry[ParentNavigationEntry="456"]

但这只给了我 RelationEntry 字段，但我需要 NavigationEntry 字段.

But this only gives me the RelationEntry Field, but I need the NavigationEntry Field.

是否可以通过单个 XPath 查询来解决此问题?

Is it possible to solve this with a single XPath query?

推荐答案

问题是:我如何获得所有具有字段的导航条目具有值的 ParentNavigationEntry456.

The question is: how do I get all navigation entries that has a Field ParentNavigationEntry with the value 456.

//NavigationEntry[
   /Relation
      /RelationEntry
         /ParentNavigationEntry = 456
]

注意:选择那些 NavigationEntry 元素，然后过滤谓词.此外，当模式众所周知时，使用 // 不是一个好习惯，因为即使在匹配之后它也会遍历整个后代树.

Note: Select those NavigationEntry elements and then filter predicate. Also, when the schema is well known it's not good practice to use // because it traverse the whole descendant tree even after a match.

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