XPath - 确定元素位置 [英] XPath - determine the element position

问题描述

我想为每个表创建一个索引(确定在 XML 中的位置)，但问题是这些表的深度不同.我计划用 XSLT 转换到 FO 来处理 XML.我知道如何做到这一点吗?

I want to create an index (determine the position in the XML) for every table but the problem is that the tables are in different depth. I plan to process the XML with XSLT transformation to FO. I Any ideas how to do this?

示例 XML

<document>
    <table> ... </table>

    <section>
        <table> ... </table>

        <subsection>
            <table> ... </table>
        </subsection>
    </section>
</document>

推荐答案

@Tomalak 的解决方案并不完全正确，在嵌套表的情况下会产生错误的结果.

@Tomalak's solution isn't completely correct and will produce wrong result in the case when there are nested tables.

这样做的原因是 XPath preceding 和 ancestor 轴不重叠.

The reason for this is that the XPath preceding and ancestor axes are non-overlapping.

给出想要的数字的一个正确的 XPath 表达式是:

count(ancestor::table | preceding::table) + 1

所以，使用:

<xsl:template match="table">
    <table id="tbl_{count(ancestor::table | preceding::table) + 1}">
        <!-- further processing -->
    </table>
</xsl:template>

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