在 Powershell 中，如何让 Select-Xml 搜索多个节点 [英] In Powershell how do I get Select-Xml to search multiple Nodes

问题描述

所以我不得不说我是使用 PowerShell 解析 XML 的新手.话虽如此，如何组合多个 -XPath 以便我可以完成构建我的表达式报告.请告诉我，我已经尝试了多种组合，但似乎没有一个适用于命名空间 XML.

So I got to say that I m new to using PowerShell for parsing out XML. With that said, how to do I combine multiple -XPath So that I can finishing building out my expression report. Please let me know, I have tried several combinations and none of them seem to work with namespace XML.

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" niaVersion="12.0.0.756" xmlns="http://something.com/something/hotfix/manifest">
    <releases>
        <release name="mid November 2017">
            <hotfixes>
                <hotfixref name="DE002" description="" defectSuite="n/a" supportEscalation="n/a" internalNotes="" customer="n/a">
                    <packages>
                        <package type="All" />
                    </packages>
                    <components>
                        <component type="" />
                        <component type="" />
                    </components>
                </hotfixref>
                <hotfixref name="DE5728" description="" defectSuite="DS001" supportEscalation="n/a" internalNotes="" customer="n/a">
                    <packages>
                        <package type="Full" />
                    </packages>
                    <components>
                        <component type="" />
                    </components>
                </hotfixref>
            </hotfixes>
        </release>
    </releases>
</manifest>




[xml]$xdoc=Get-Content $PSScriptRoot\Manifest.xml
$ns = @{test ="http://something.com/something/hotfix/manifest"}
$ver = Select-Xml -Xml $xdoc -XPath '//test:release' -Namespace $ns 
$hfu = Select-Xml -Xml $xdoc -XPath '//test:hotfixref' -Namespace $ns 
foreach ($v in $ver){
$v | Select-Object -ExpandProperty node 
 $hfu |  Select-Object -ExpandProperty node

推荐答案

我不明白为什么您需要同时找到修补程序和发布节点.Release 是 hotfixes 的父节点，因此只需找到所有 release-nodes 并在循环中访问其子节点即可找到相关的 hotfixes.例如:

I can't understand why you need to find both hotfixes and release-nodes. Release is a parent of hotfixes, so simply find all release-nodes and access its child nodes in a loop to find the relevant hotfixes. Ex:

$xdoc = [xml]@"
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" niaVersion="12.0.0.756" xmlns="http://something.com/something/hotfix/manifest">
    <releases>
        <release name="mid November 2017">
            <hotfixes>
                <hotfixref name="DE002" description="" defectSuite="n/a" supportEscalation="n/a" internalNotes="" customer="n/a">
                    <packages>
                        <package type="All" />
                    </packages>
                    <components>
                        <component type="" />
                        <component type="" />
                    </components>
                </hotfixref>
                <hotfixref name="DE5728" description="" defectSuite="DS001" supportEscalation="n/a" internalNotes="" customer="n/a">
                    <packages>
                        <package type="Full" />
                    </packages>
                    <components>
                        <component type="" />
                    </components>
                </hotfixref>
            </hotfixes>
        </release>
    </releases>
</manifest>
"@



$ns = @{test ="http://something.com/something/hotfix/manifest"}
$releases = Select-Xml -Xml $xdoc -XPath '//test:release' -Namespace $ns  
foreach ($r in $releases){
    "$($r.node.name) contains the following hotfixes:"
    $r.node.hotfixes.hotfixref | Select-Object Name, description, defectSuite
}

输出:

mid November 2017 contains the following hotfixes:

name   description defectSuite
----   ----------- -----------
DE002              n/a
DE5728             DS001

如果你真的想要一个 xpath-query 来查找这两种类型，那么使用 | (OR) 来分隔 xpath-queries.例如:

If you really want one xpath-query to find both types, then use | (OR) to separate the xpath-queries. Ex:

Select-Xml -Xml $xdoc -XPath '//test:release|//test:hotfixref' -Namespace $ns

Node      Path        Pattern
----      ----        -------
release   InputStream //test:release|//test:hotfixref
hotfixref InputStream //test:release|//test:hotfixref
hotfixref InputStream //test:release|//test:hotfixref

这样做的问题是您需要逻辑来检测您正在访问的节点类型，因为它可能是发布的，也可能是hotfixref.您还需要额外的逻辑来了解哪个 hotfixref 属于哪个版本.

The problem with this is that you will need logic to detect what type of node you're accessing since it may be release or it may be hotfixref. You will also need extra logic to understand which hotfixref belongs to which release.

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