Python:是否可以使用 xmlrpclib 设置客户端端口? [英] Python: Is it possible to set the clientport with xmlrpclib?

问题描述

是否可以为 xmlrpc-connection 设置客户端端口?

Is it possible to set the clientport for the xmlrpc-connection?

我想说:

客户端应该通过特定的客户端端口创建一个 ServerProxy 对象

Client should make a ServerProxy-object to over a specific client port

或伪代码如下:

serv = xmlrpclib.ServerProxy("server:port","overSpecificClientPort").

推荐答案

尝试定义自定义传输.这应该是这样的:

Try to define a custom transport. This should be something like that:

import xmlrpclib, httplib

class sourcedTransport(xmlrpclib.Transport):
    def setSource(self, src):
        self.src = src
    def make_connection(self, host):
        h = httplib.HTTPConnection(host, source_address= self.src)
        return h

srcPort = 43040
srcAddress = ('', srcPort)
p = sourcedTransport()
p.setSource(srcAddress)
server = xmlrpclib.ServerProxy("server:port", transport=p)

错误修复 httplib.HTTP => httplib.HTTPConnection

bug fix httplib.HTTP => httplib.HTTPConnection

并在 python 2.7(但不是之前)中检查它是否有效

And checked that it works, in python 2.7 (but not before)

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