选择 `text()` 1) 在给定节点之前但 2) 也是另一个给定节点的后代 [英] Select `text()` that 1) precede a given node but 2) are also descendants of another given node
本文介绍了选择 `text()` 1) 在给定节点之前但 2) 也是另一个给定节点的后代的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
这是this，但不幸的是，该问题的答案不适用.
假设我有以下 XML:
<div id="global-header">标题<div id="a"><h3>一些标题</h3><p>文本 1<b>粗体</b></p><div><p>abc</p><p>文本2</p><p>def</p>
我想
- 找到值为text 2"的
节点；(假设我们只有一个这样的)，然后 - 查找在此特定
之前但也是节点的后代的所有节点(您可以使用像[@id='a']之类的东西来定位它)，最后- 从步骤 2 中提取
text().所需的输出应如下所示:
一些标题文本1胆大美国广播公司需要注意的是
- 前面的节点可以包含任意节点类型，而不仅仅是
和. <p>text 2</p>节点可以任意嵌入到树的深处，因此 xpath 就像.//p[text()=text 2"]/preceding-sibling::*只会提取<p>abc</p>而忽略其他.
解决方案你可以试试这个 XPath 表达式:
//p[.='text 2']/preceding::text()[ancestor::div[@id='a']]这种方法的缺点是
text()节点可能没有明确分开，而是合并为子元素.要将它们分开，您需要某种 for 循环.This is a follow-up question of this, but unfortunately the answer from that question doesn't apply.
Say I have the following XML:
<body> <div id="global-header"> header </div> <div id="a"> <h3>some title</h3> <p>text 1 <b>bold</b> </p> <div> <p>abc</p> <p>text 2</p> <p>def</p> </div> </div> </body>I want to
- find the
<p>node whose value is "text 2" (assume we only have exactly one such<p>), and then - find all the nodes that precede this particular
<p>but are also descendants of the<div id='a'>node(you can use something like[@id='a']to locate it), and finally - extract
text()from step 2.
The desired output should look like:
some title text 1 bold abcThe caveat is that
- the preceding nodes may contain arbitrary node type, not only
<h3>and<p>. - the
<p>text 2</p>node may be embeded arbitrarly deep in the tree, hence xpath like.//p[text()="text 2"]/preceding-sibling::*would only extract<p>abc</p>and leave out others.
解决方案You can try this XPath expression:
//p[.='text 2']/preceding::text()[ancestor::div[@id='a']]The disadvantage of this approach is that the
text()nodes may not be clearly separated, but rather merged for the sub-elements. To separate them, you'd need some kind of for-loop.这篇关于选择 `text()` 1) 在给定节点之前但 2) 也是另一个给定节点的后代的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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