找到 xpath 来选择以下同级，而不是在另一个与 xsl 中的当前标签相同的标签之后 [英] find xpath to pick following sibling not after another tag same as current in xsl

问题描述

当我在下面匹配 A 或 A1 模板时，我想获得以下兄弟 C，仅用于第二个 A 或 A1:

I would like to get the following sibling C when I'm matching A or A1 template in the following, for the second A or A1 only:

<root>
  <A/>  <!-- first A -->
  <B/>
  <A/>  <!-- second A -->
  <C/>
  <A1/>
  <B/>
  <A1/>
  <B/>
  <C/>
</root>

• 如果我匹配第一个 A，我不必检索任何东西，因为在我的 C 标记之前还有另一个 A.

  • If I'm matching the first A, I have not to retrieve anything as there is another A before my C tag.

    如果我匹配第二个 A，我必须检索 C 标签.

    If I'm matching the second A, I have to retrieve the C tag.

    我尝试了以下方法但没有成功:

    I tried the following without success:

     <xsl:template match="A|A1">
         <xsl:if test="following-sibling::C[preceding-sibling::A|A1[1] = .]">
    

    似乎在每种情况下都是如此，但为什么呢?

    It seems to be true in every case but why?

    推荐答案

    在 XSLT 2.0 中，您可以使用类似

    In XSLT 2.0 you could use a test like

    following-sibling::C[
        (preceding-sibling::A|preceding-sibling::A1)[last()] is current()]
    

    找出所有最接近的前面的 A 或 A1 是您首先想到的 C.对于 XSLT 1.0，您必须比较 generate-id 值而不是使用 is

    to find all the Cs whose nearest preceding A or A1 is the one you first thought of. For XSLT 1.0 you'd have to compare generate-id values instead of using is

    following-sibling::C[
         generate-id((preceding-sibling::A|preceding-sibling::A1)[last()])
       = generate-id(current())]
    

    这将选择

    <root>
      <A/>  <!-- nothing -->
      <B/>
      <A/>  <!-- C1 -->
      <C/>  <!-- this is C1 -->
      <A1/> <!-- nothing -->
      <B/>
      <A1/> <!-- C2 -->
      <B/>
      <C/>  <!-- this is C2 -->
    </root>
    

    <小时>

    您的原始测试

    ---

    Your original test

    following-sibling::C[preceding-sibling::A|A1[1] = .]
    

    相当于

    following-sibling::C[
      ( preceding-sibling::A | (child::A1[1]) ) = .]
    

    并且会选择所有后面的 C 兄弟姐妹，对于他们(a)任何他们前面的 A 兄弟姐妹或(b)他们的第一个 A1 子元素具有与 C 本身相同的字符串值.文档中的所有 C 元素都满足此谓词，因为每个元素都具有空字符串值.

    and would select all following C siblings for whom either (a) any of their preceding A siblings or (b) their first A1 child has a string value the same as that of the C itself. All the C elements in your document satisfy this predicate as every element has the empty string value.

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