XSLT 选择第二次出现的属性 [英] XSLT select the second occurrence of an attribute
问题描述
有没有一种动态的方法来获取属性的第二次出现?
Is there a dynamic way to get the 2nd occurrence of an attribute ?
对于这个 XML 示例,我想将 SummaryCell/@Name 值的前 12 个值放入变量 Month01、Month02 等中;
For this XML example, I'd like to get the first 12 values of the SummaryCell/@Name value into a variable Month01, Month02, and so on;
<SummaryHeader>
<SummaryColumnGroup Name="2014">
<SummaryCell Name="Feb14" Type="Text" Value="Feb"/>
<SummaryCell Name="Jan14" Type="Text" Value="Jan"/>
</SummaryColumnGroup>
<SummaryColumnGroup Name="2013">
<SummaryCell Name="Dec13" Type="Text" Value="Dec"/>
<SummaryCell Name="Nov13" Type="Text" Value="Nov"/>
<SummaryCell Name="Oct13" Type="Text" Value="Oct"/>
<SummaryCell Name="Sep13" Type="Text" Value="Sep"/>
<SummaryCell Name="Aug13" Type="Text" Value="Aug"/>
<SummaryCell Name="Jul13" Type="Text" Value="Jul"/>
<SummaryCell Name="Jun13" Type="Text" Value="Jun"/>
<SummaryCell Name="May13" Type="Text" Value="May"/>
<SummaryCell Name="Apr13" Type="Text" Value="Apr"/>
<SummaryCell Name="Mar13" Type="Text" Value="Mar"/>
<SummaryCell Name="Feb13" Type="Text" Value="Feb"/>
<SummaryCell Name="Jan13" Type="Text" Value="Jan"/>
</SummaryColumnGroup>
以下是我用过的XSL;
The following is the XSL I have used;
<xsl:variable name="Month01" select="//SummaryHeader/SummaryColumnGroup/SummaryCell[1]/@Name"/>
<xsl:variable name="Month02" select="//SummaryHeader/SummaryColumnGroup/SummaryCell[2]/@Name"/>
<xsl:variable name="Month03" select="//SummaryHeader/SummaryColumnGroup/SummaryCell[3]/@Name"/>
期望的输出:
<Month01>Feb14</Month01>
<Month02>Jan14</Month02>
<Month03>Dec13</Month03>
实际输出:
<Month01>Feb14</Month01>
<Month02>Jan14</Month02>
<Month03>Oct13</Month03>
发生的情况是,SummaryCell[3] 实际上选取了以下 SummaryColumnGroup 的第 3 个 SummaryCell,而不是迭代到第 3 个出现的 SummaryCell.
What happens is, SummaryCell[3] actually picks up the the 3rd SummaryCell of the following SummaryColumnGroup, and not iterates through to the 3rd occurrences of SummaryCell.
注意:SummaryColumnGroup 内的SummaryCell 数量是动态的,具体与上面的例子不同.
Note: The number of SummaryCell within a SummaryColumnGroup is dynamic, not specifically the same as the above example.
推荐答案
我想获取 SummaryCell/@Name 值的前 12 个值
I'd like to get the first 12 values of the SummaryCell/@Name value
有一个更好的方法来做到这一点.以下样式表:
There is a much better way to do that. The following stylesheet:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<root>
<xsl:for-each select="SummaryHeader/SummaryColumnGroup/SummaryCell[count(preceding::SummaryCell) < 12 ]">
<Month num="{position()}"><xsl:value-of select="@Name"/></Month>
</xsl:for-each>
</root>
</xsl:template>
</xsl:stylesheet>
当应用于(更正的)输入:
<SummaryHeader>
<SummaryColumnGroup Name="2014">
<SummaryCell Name="Feb14" Type="Text" Value="Feb"/>
<SummaryCell Name="Jan14" Type="Text" Value="Jan"/>
</SummaryColumnGroup>
<SummaryColumnGroup Name="2013">
<SummaryCell Name="Dec13" Type="Text" Value="Dec"/>
<SummaryCell Name="Nov13" Type="Text" Value="Nov"/>
<SummaryCell Name="Oct13" Type="Text" Value="Oct"/>
<SummaryCell Name="Sep13" Type="Text" Value="Sep"/>
<SummaryCell Name="Aug13" Type="Text" Value="Aug"/>
<SummaryCell Name="Jul13" Type="Text" Value="Jul"/>
<SummaryCell Name="Jun13" Type="Text" Value="Jun"/>
<SummaryCell Name="May13" Type="Text" Value="May"/>
<SummaryCell Name="Apr13" Type="Text" Value="Apr"/>
<SummaryCell Name="Mar13" Type="Text" Value="Mar"/>
<SummaryCell Name="Feb13" Type="Text" Value="Feb"/>
<SummaryCell Name="Jan13" Type="Text" Value="Jan"/>
</SummaryColumnGroup>
</SummaryHeader>
将返回以下结果:
<?xml version="1.0" encoding="UTF-8"?>
<root>
<Month num="1">Feb14</Month>
<Month num="2">Jan14</Month>
<Month num="3">Dec13</Month>
<Month num="4">Nov13</Month>
<Month num="5">Oct13</Month>
<Month num="6">Sep13</Month>
<Month num="7">Aug13</Month>
<Month num="8">Jul13</Month>
<Month num="9">Jun13</Month>
<Month num="10">May13</Month>
<Month num="11">Apr13</Month>
<Month num="12">Mar13</Month>
</root>
我认为对
元素进行编号不是一个好方法,但是您当然可以通过使用
从位置计算名称.
I don't think having numbered <MonthXX>
elements is a good way to go, but of course you could do that by using <xsl:element>
to calculate the name from position.
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