如何使用 XPATH 解析 XML [英] How to parse XML using XPATH
问题描述
我想扫描以下 XML 并根据条件 name=task2 和 value=efg 获取 id 的值.
I want to scan following XML and fetch value of id based on condition name=task2 and value=efg.
<node1>
<node2>
<node3>
<id>ABC-123</id>
<condition>
<task name="task1" operation="and" value="abc" />
<task name="task2" operation="and" value="efg" />
<task name="task3" operation="and" value="hij" />
<task name="task4" operation="or" value="klm" />
<task name="task5" operation="and" value="nop" />
<task name="task6" value="uvw" />
</condition>
</node3>
<node3>
<id>XYZ-987</id>
<condition>
<task name="task1" operation="and" value="cde" />
<task name="task2" operation="and" value="abc" />
<task name="task5" operation="and" value="nop" />
</condition>
</node3>
<node3>
<id>RST-567</id>
<condition>
<task name="task2" operation="and" value="efg" />
<task name="task8" operation="and" value="jkl" />
<task name="task9" operation="and" value="rst" />
<task name="task10" value="xyz" />
</condition>
</node3>
</node2>
</node1>
我可以使用
String expression = "//node3/condition/task[@name='"+condition.getKey()+"' and @value='"+condition.getValue()+"']";
但不是使用以下代码的 id 的值
But not the value of id using following code
String expression = "//node3/condition/task[@name='"+condition.getKey()+"' and @value='"+condition.getValue()+"']/node3/id";
如何获取正确结果的值ABC-123"和RST-567"?
How to get values "ABC-123" and "RST-567" which would be the correct result?
参考以下博客和 w3c 链接
https://xjaphx.wordpress.com/2011/12/24/android-xml-adventure-parsing-xml-using-xpath/
http://www.w3schools.com/xml/xml_xpath.asp
http://www.w3schools.com/xsl/xpath_operators.asp
Referring following blog and w3c links
https://xjaphx.wordpress.com/2011/12/24/android-xml-adventure-parsing-xml-using-xpath/
http://www.w3schools.com/xml/xml_xpath.asp
http://www.w3schools.com/xsl/xpath_operators.asp
推荐答案
您可以嵌套谓词([]
中的表达式)来实现,例如:
You can nest predicates (expression in []
) to achieve that, for example :
//node3[condition/task[@name='task2' and @value='efg']]/id
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