使用Java中的XPath解析XML [英] Parsing XML with XPath in Java

问题描述

我的XML结构与此类似：

I have a XML with a structure similar to this:

<category>
   <subCategoryList>
      <category>

      </category>
      <category>
         <!--and so on -->
      </category>
   </subCategoryList>
</category>

我有一个具有子类别 list（ List< Category> ）。我正在尝试使用XPath解析此XML文件，但我无法获取类别的子类别。

I have a Category class that has a subcategory list (List<Category>). I'm trying to parse this XML file with XPath, but I can't get the child categories of a category.

如何使用XPath执行此操作？有没有更好的方法呢？

How can I do this with XPath? Is there a better way to do this?

推荐答案

此链接包含您需要的一切。简而言之：

This link has everything you need. In shorts:

 public static void main(String[] args) 
   throws ParserConfigurationException, SAXException, 
          IOException, XPathExpressionException {

    DocumentBuilderFactory domFactory = 
    DocumentBuilderFactory.newInstance();
          domFactory.setNamespaceAware(true); 
    DocumentBuilder builder = domFactory.newDocumentBuilder();
    Document doc = builder.parse("persons.xml");
    XPath xpath = XPathFactory.newInstance().newXPath();
       // XPath Query for showing all nodes value
    XPathExpression expr = xpath.compile("//person/*/text()");

    Object result = expr.evaluate(doc, XPathConstants.NODESET);
    NodeList nodes = (NodeList) result;
    for (int i = 0; i < nodes.getLength(); i++) {
     System.out.println(nodes.item(i).getNodeValue()); 
    }
  }

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