将 XML 日期时间反序列化为 UTC [英] Deserialize XML dateTime to UTC

问题描述

我正在使用包含 XSD 元素的 XML 网络服务，例如:

I am consuming an XML webservice with XSD elements such as:

<xs:element nillable="true" type="xs:dateTime" name="ENDDATE"/>

XML 可能如下所示:

XML might look like the following:

<ENDDATE>2016-08-01T18:35:49+04:00</ENDDATE>

我使用 XSD.exe 自动生成 C# 类，当我检查这些类时，DateTime 对象将包含系统本地时间的时间，Kind==Local.

I used XSD.exe to autogenerate C# classes, when I inspect these the DateTime object will contain the time in system-local time, with Kind==Local.

有没有一种方法可以强制 DateTime 实例使用 UTC 时间，而无需为每个此类字段手动破解自动生成的类(有很多)?

Is there a way I can force the DateTime instances to be in UTC time without manually hacking the auto-generated classes for every such field (there are rather a lot)?

推荐答案

我认为您无法使用 XSD 调整此行为(请参阅 此处).因此，您应该更新(hack)自动生成的类并执行类似于 那里:

I think that you can't tune this behavior using XSD (see here). So you should update(hack) auto-generated classes and do something like described there:

[XmlIgnore()]
public DateTime Time { get; set; }

[XmlElement(ElementName = "Time")]
public string XmlTime
{
    get { return XmlConvert.ToString(Time, XmlDateTimeSerializationMode.RoundtripKind); }
    set { Time = DateTimeOffset.Parse(value).DateTime; }
}

或者，如果您真的经常自动生成这些类，您可以为它们引入包装器，这将透明地将 DateTime 转换为 UTC.

Or, if you really often auto-generate those classes, you can introduce wrappers for them, which will transparently convert DateTime to UTC.

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