XSLT 默认模板混淆 [英] XSLT default template confusion

问题描述

我对 XSLT 处理器节点的方式感到困惑，假设我有一个这样的 XML 文档:

I'm getting a confusion on the way XSLT processors nodes, suppose I have an XML Doc like this:

<object>
        <animal>
                <man men="asd">man1</man>
                <man>man2</man>
                <man>man3</man>
                <man>man4</man>
                <cat>cat1</cat>
                <cat>cat2</cat>
                <cat>cat3</cat>
                <cat>cat4</cat>
        </animal>
        <vehicule>
                <car>car1</car>
                <car>car2</car>
                <car>car3</car>
                <car>car4</car>
        </vehicule>
</object>

当我有一个没有任何模板匹配的 XSLT 时，如下所示，它返回所有文本节点而没有属性节点，没关系

When I have an XSLT without any template matching like the one below, it returns all text nodes and no attribute nodes, that's OK

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
</xsl:stylesheet>

但是当我有一个像下面这样的时，它不会返回任何东西:

But when I have one like the one below, it doesn't return anything:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
        <xsl:template match="object">
        </xsl:template>
</xsl:stylesheet>

是不是如果我有一个父节点的显式模板，我就应该有一个父节点的所有子节点的显式模板?

Is it that if I have an explicit template for a parent node, I should have an explicit template for all child nodes of the parent nodes?

推荐答案

您所看到的只是 内置规则，输出节点的文本值并将模板应用于其所有子节点.

What you are seeing are simply the effects of the built-in rules, which output the text value of a node and apply the templates to all its children.

如果您覆盖内置模板，那么您的模板就会生效.您想应用所有子项的内置规则<代码>对象:

If you overwrite the built-in templates, well, your template takes effect. You want to apply the built-in rules for all children of object:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
  <xsl:template match="object">
    <xsl:apply-templates select="*" />
  </xsl:template>
</xsl:stylesheet>

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