应用模板上选择属性的 xslt 处理 [英] xslt processing on select attribute on apply-templates

问题描述

我有一个如下的 XSLT 并将这个 xslt 应用到输入 xml[粘贴在下面]，除了需要澄清的一件事外，它工作正常.

I have a XSLT as below and apply this xslt into the input xml[pasted below], it is working fine except one thing that need to clarify.

这是输入的xml

<Test>
  <Experiment id='1'>
    <Dish1>
      <Conditions pressure='x' temp='y'/>
      <Measurement timeStamp='8am' reading='y'/>
    </Dish1>
    <Dish2>
      <Conditions pressure='x' temp='y'/>
      <Measurement timeStamp='8am' reading='y'/>
    </Dish2>
    <Dish1>
      <Conditions pressure='x' temp='y'/>
      <Measurement timeStamp='2pm' reading='y'/>
    </Dish1>
    <Dish2>
      <Conditions pressure='x' temp='y'/>
      <Measurement timeStamp='2pm' reading='y'/>
    </Dish2>
   </Experiment>
   <Experiment id='2'>
    <Dish1>
      <Conditions pressure='x' temp='y'/>
      <Measurement timeStamp='9am' reading='y'/>
    </Dish1>
    </Experiment>
</Test>

这是 xslt

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
   <xsl:output method="xml" indent="yes"/>

   <xsl:template match="Experiment">
      <xsl:copy>
         <xsl:apply-templates select="@*" />
         <xsl:for-each-group select="*" group-by="local-name()">
            <xsl:copy>
               <xsl:apply-templates select="current-group()" />

            </xsl:copy>
         </xsl:for-each-group>
      </xsl:copy>
   </xsl:template>

   <xsl:template match="Experiment/*">
      <Observation>
         <xsl:apply-templates select="*/@*" />
      </Observation>
   </xsl:template>

   <xsl:template match="@*|node()">
      <xsl:copy>
         <xsl:apply-templates select="@*|node()"/>
      </xsl:copy>
   </xsl:template>

</xsl:stylesheet>

这是转换工作正常.但是，如果我在 xslt 上进行如下更改，则会出错.有什么想法吗?

This is transformation is working fine. But, if i change as below on the xslt, then, it is getting error. Any idea?

<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="."/>
</xsl:copy>
</xsl:template>

即，在最后一场比赛中，我已将 <xsl:apply-templates select="@*|node()"/> 更改为 <xsl:apply-templates select="."/>

I.e., On the last match, I have changed from <xsl:apply-templates select="@*|node()"/> to <xsl:apply-templates select="."/>

推荐答案

. 表示当前节点.当您将模板应用于 . 时，您将它们应用于当前上下文.

. means the current node. When you apply-templates to ., you're applying them to the current context.

在您的情况下，模板将匹配 Test，输出它的副本，并将模板应用于自身.然后它会再次匹配，基本上让你陷入无限循环.

In your case, the template will match Test, output a copy of it, and apply-templates to itself. It will then match again basically putting you into an endless loop.

通过在 node()|@* 上执行应用模板，您将模板应用于所有子节点和属性.

By doing the apply-templates on node()|@*, you're applying templates to all child nodes and attributes.

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