XSLT 如何应用递归从平面文件转换为嵌套树 [英] XSLT How to apply recursion to transform from a flat file to a nested tree

查看:27
本文介绍了XSLT 如何应用递归从平面文件转换为嵌套树的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我知道还有其他几个与此类似的问题/答案,但我还没有读过一个解决我对这种转换的困惑的问题/答案.我需要从这种格式移动 XML 文档:

I know that there are several other question/answers similar to this, but I haven't read one that addresses my confusion over this transform. I need to move an XML document from this format:

<root>
    <row>
        <t0>1</t0>
        <title>Main Title</title>
    </row>
    <row>
        <t0>2</t0>
        <title>Secondary Title</title>
        <note>Note</note>
    </row>
    <row>
        <t0>3</t0>
        <title>Tertiary Title</title>
    </row>
    <row>
        <t0>3</t0>
        <title>Another Title</title>
    </row>
    <row>
        <t0>2</t0>
        <title>A Second Secondary Title</title>
        <note>Note</note>
    </row>
    <row>  
        <t0>3</t0>
        <title>Third Level Title</title>
    </row>
    <row> 
        <t0>3</t0>
        <title>Title at Level Three</title>
    </row>
</root>

到这种格式:

<root>
    <header>List</header>
    <t01>
        <title>Main Title</title>
        <t02>
            <title>Secondary Title</title>
            <note>Note</note>
            <t03>
                <title>Tertiary Title</title>
            </t03>
            <t03>
                <title>Another Title</title>
            </t03>
        </t02>
        <t02>
            <title>A Second Secondary Title</title>
            <note>Note</note>
            <t03>
                <title>Third Level Title</title>
            </t03>
            <t03>   
                <title>Title at Level Three</title>
            </t03>
        </t02>
    </t01>
</root>

我正在使用 XSLT 2.0 并且我对递归地应用 for-each-group 感到厌烦.感谢您的时间 &麻烦.

I'm using XSLT 2.0 and I'm getting hung up on applying for-each-group recursively. Thanks for your time & trouble.

推荐答案

对于 XSLT 2.0,我强烈建议将 for-each-grouping 与递归函数或模板一起使用;下面是一个使用函数的示例:

With XSLT 2.0 I would strongly suggest to use the for-each-grouping together with a recursive function or template; below is a sample using a function:

<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  version="2.0"
  xmlns:xs="http://www.w3.org/2001/XMLSchema"
  xmlns:mf="http://example.com/mf"
  exclude-result-prefixes="xs mf">

<xsl:output indent="yes"/>

<xsl:function name="mf:group" as="element()*">
  <xsl:param name="elements" as="element(row)*"/>
  <xsl:param name="level" as="xs:integer"/>
  <xsl:for-each-group select="$elements" group-starting-with="row[t0 = $level]">
    <xsl:element name="t{format-number($level, '00')}">
      <xsl:copy-of select="* except t0"/>
      <xsl:sequence select="mf:group(current-group() except ., $level + 1)"/>
    </xsl:element>
  </xsl:for-each-group>
</xsl:function>

<xsl:template match="root">
  <xsl:copy>
    <header>List</header>
    <xsl:sequence select="mf:group(row, 1)"/>
  </xsl:copy>
</xsl:template>

</xsl:stylesheet>

这篇关于XSLT 如何应用递归从平面文件转换为嵌套树的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆