使用XSLT 1.0将元素连接行和列名称的平面XML表数据转换为嵌套XML [英] Convert flat XML table data where elements are concatenated row and column names into nested XML, using XSLT 1.0

问题描述

我有XML输出代表这样输出的数据表:

I have XML output representing a table of data being output like this:

<results>
  <Row1.Name>Henry</Row1.Name>
  <Row1.Id>P162</Row1.Id>
  <Row1.Age>23</Row1.Age>
  <Row2.Name>John</Row2.Name>
  <Row2.Id>P137</Row2.Id>
  <Row2.Age>27</Row2.Age>
  <Row3.Name>Mary</Row3.Name>
  <Row3.Id>L493</Row3.Id>
  <Row3.Age>32</Row3.Age>
</results>

，我想将其转换为此:

<results>
  <Row>
    <Name>Henry</Name>
    <Id>P162<Id>
    <Age>23</Age>
  </Row>
  <Row>
    <Name>John</Name>
    <Id>P137<Id>
    <Age>27</Age>
  </Row>
  <Row>
    <Name>Mary</Name>
    <Id>L493<Id>
    <Age>32</Age>
  </Row>
</results>

我正在使用的应用程序迫使我使用XSLT 1.0，我敢肯定这确实很简单，但是我今天遇到了麻烦，所以我想问一下我的虚拟同事.

The application I am working with forces me to use XSLT 1.0, and I'm sure this is really simple, but I'm having a mental block today so I figured I'd ask my virtual colleagues.

有人有什么主意吗?

注意:修改了所需的输出，以不显示迭代行号，这正是我想要的.

NOTE: Amended the desired output to not show iterative row numbers, which is what I want.

还没有什么工作要做.还在玩着不同的东西.

Haven't got anything close to working yet. Still playing around with different things.

我想可以这样写:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:template match="/">
    <xsl:variable name="Row" select="distinct-values(*[contains(name(),'Row')])" />
           <xsl:for-each select="$Row">
               <xsl:variable name="rowName" select="name()" />
               <Row>
                   <xsl:for-each select="*[contains(name(),$Row)]">
                       <xsl:copy select="." />
                   </xsl:for-each>
               </Row>
           </xsl:for-each>
    </xsl:template>
</xsl:stylesheet>

产生这个:

<results>
    <Row>
        <Row1.Name>Henry</Row1.Name>
        <Row1.Id>P162</Row1.Id>
        <Row1.Age>23</Row1.Age>
    </Row>
    <Row>
        <Row2.Name>John</Row2.Name>
        <Row2.Id>P137</Row2.Id>
        <Row2.Age>27</Row2.Age>
    </Row>
    <Row>
        <Row3.Name>Mary</Row3.Name>
        <Row3.Id>L493</Row3.Id>
        <Row3.Age>32</Row3.Age>
   </Row>
</results>

，然后返回并使用以下命令删除所有Row#前缀:

and then go back and remove all the Row# prefixes with:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

    <xsl:template match="@* | node()">
        <xsl:copy>
            <xsl:apply-templates select="@* | node()"/>
        </xsl:copy>
    </xsl:template>

    <xsl:template match="/*[contains(name(),'.')]">
        <xsl:variable name="Name" select="substring-after(name(),'.')" />
        <xsl:element name="{$Name}">
            <xsl:value-of select="." />
        </xsl:element>
    </xsl:template>

</xsl:stylesheet>

虽然这两种转换都不起作用，但我认为我不能在XSLT 1.0中使用distinct-values

Neither transform works though and I don't think I can use distinct-values with XSLT 1.0

推荐答案

这是一个分组问题，而在XSLT 1.0中解决此类问题的标准方法称为孟席亚分组.您可以定义一个键，该键以所需的方式对元素进行分组，然后对generate-id使用技巧将每个组仅处理一个元素.在这种情况下，您希望按点名称之前的部分将元素分组:

This is a grouping problem, and the standard approach to such problems in XSLT 1.0 is called Muenchian grouping. You define a key that groups your elements in the way you want and then use a trick with generate-id to process just one element per group. In this case you want to group elements by the part of their name before the dot:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">

  <xsl:key name="elementByRow" match="/*/*"
           use="substring-before(name(), '.')" />

  <xsl:template match="/results">
    <results>
      <!-- pick out the first RowN.* element for each N -->
      <xsl:apply-templates select="*[generate-id() =
         generate-id(key('elementByRow', substring-before(name(), '.'))[1])]" />
    </results>
  </xsl:template>

  <xsl:template match="*">
    <Row>
      <!-- process _all_ the elements that belong to this row -->
      <xsl:for-each select="key('elementByRow', substring-before(name(), '.'))">
        <xsl:element name="{substring-after(name(), '.')}">
          <xsl:value-of select="." />
        </xsl:element>
      </xsl:for-each>
    </Row>
  </xsl:template>
</xsl:stylesheet>

这篇关于使用XSLT 1.0将元素连接行和列名称的平面XML表数据转换为嵌套XML的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！