$lookup 为子数组中的每个元素 [英] $lookup for each element within a sub-array

问题描述

所以在我的数据库中，我有 3 个集合，它们看起来像这样:

So in my Database, I have the 3 collections, and they look like this:

客户:

customers = [
  {_id: 1, username: "jack", ... },
  {_id: 2, username: "jane", ... }
  ...
]

评论:

reviews = [
  { _id: 1, customerID: 1, message: "my message", ...}
  ...
]

评论:

comments = [
  { _id: 1, reviewID: 1, customerID: 2, message: "my response" ...}
  ...
]

客户可以发表评论，也可以评论其他评论.所以，我想要的是一个 mongodb aggregation 查询:

Customers can post reviews, and can also comment on other reviews. So, what I want is a mongodb aggregation query to:

1. 检索评论.

1. Retrieve the reviews.

进行评论的客户的数据.

The data of the customer who made the review.

对该评论的评论.

对该评论发表评论的客户的数据.

The data of the customers who made the comment on that review.

即

reviews = [
  {
    _id: 1,
    username: "jack",
    message: "my message"
    comments: [
      { _id: 1, username: "jane", message: "my response", ...},
      ...
    ]
    ...
  }
  ...
]

推荐答案

您可以从 comments 集合和 $lookup with customers 得到 customer 名字，然后你就可以$group 评论和 $lookup 两次(使用 reviews 和 customer).每次你知道这是一对一的关系时，你可以使用 $unwind 在 $lookup 之后.试试:

You can start from comments collection and $lookup with customers to get customer name, then you can $group all comments by review and $lookup twice (with reviews and customer). Every time you know that it's a one-to-one relationship you can use $unwind after $lookup. Try:

db.comments.aggregate([
    {
        $lookup: {
            from: "customers",
            localField: "customerID",
            foreignField: "_id",
            as: "customer"
        }
    },
    {
        $unwind: "$customer"
    },
    {
        $project: {
            _id: 1,
            reviewID: 1,
            username: "$customer.username",
            message: 1
        }
    },
    {
        $group: {
            _id: "$reviewID",
            comments: { $push: { _id: "$_id", username: "$username", message: "$message" } }
        }
    },
    {
        $lookup: {
            from: "reviews",
            localField: "_id",
            foreignField: "_id",
            as: "review"
        }
    },
    {
        $unwind: "$review"
    },
    {
        $lookup: {
            from: "customers",
            localField: "review.customerID",
            foreignField: "_id",
            as: "customer"
        }
    },
    {
        $unwind: "$customer"
    },
    {
        $project: {
            _id: 1,
            message: "$review.message",
            username: "$customer.username",
            comments: 1
        }
    }
])

输出:

{ "_id" : 1, "comments" : [ { "_id" : 1, "username" : "jane", "message" : "my response" } ], "message" : "my message", "username" : "jack" }

如果您想从 reviews 开始并将其过滤为单个电影，则可以使用 $lookup 与自定义管道

If you want to start from reviews and filter it out to single movie you can then you can use $lookup with custom pipeline

db.reviews.aggregate([
    {
        $match: {
            movieId: 1,
        }
    },
    {
        $lookup: {
            from: "customers",
            localField: "customerID",
            foreignField: "_id",
            as: "customer"
        }
    },
    {
        $unwind: "$customer"
    },
    {
        $lookup: {
            from: "comments",
            let: { reviewId: "$_id" },
            pipeline: [
                {
                    $match: { $expr: { $eq: [ "$$reviewId", "$reviewID" ] } }
                },
                {
                    $lookup: {
                        from: "customers",
                        localField: "customerID",
                        foreignField: "_id",
                        as: "customer"
                    }
                },
                {
                    $unwind: "$customer"
                },
                {
                    $project: {
                        _id: 1,
                        message: 1,
                        username: "$customer.username"
                    }
                }
            ],
            as: "comments"
        }
    },
    {
        $project: {
            _id: 1,
            message: 1,
            username: "$customer.username",
            comments: 1
        }
    }
])

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