算法:IndexError:列表索引超出范围(Python) [英] Algorithm: IndexError: list index out of range (Python)

问题描述

我是 Python 新手，我想知道为什么我的程序在第 4 行显示IndexError: list index out of range".任何人都可以帮忙.

I'm new to python and I wanted to know why my program is displaying "IndexError: list index out of range" for line 4. Can anyone please help.

# A is the array and N is the size of the array.
A =[1,78,46,4,34,10,50,2]
N = len(A)
def Algorithm(A,N):
    #B <- Array[N]
    B = A[N]
    B=[0]*N
    for i in range(1,N):
        B[A[i]]+=1
        i=1
    #for i <-- 1 to N
    for j in range(1,N):
    #for k <-- to B[j]
        for k in range(0,B[j]):
            A[i]=j
            i+=1
    return

Algorithm(A,N)
print(A)

错误:

  2 N = len(A)
  3 def Algorithm(A,N):
  4     B = A[N]
  5     B=[0]*N
  6     for i in range(1,N):

IndexError: 列表索引超出范围

IndexError: list index out of range

推荐答案

所以 List index out of range 来自 B = A[N] 因为 N 代表A 的总长度但是，列表元素的索引从 0 到 N-1，这为您提供了长度 (N-1) - 0 + 1 =>否.如果要将 B 分配给 A 的最后一个元素，可以通过 B = A[N-1] 或 B = A[-1]，因为负索引从末尾指向列表的元素.但是，如果您重新声明 B = [0] * N，您可以取消第一个赋值

So the List index out of range comes from B = A[N] because N represents the total length of A. However, elements of a list are indexed from 0 up to N-1, which gives you the length (N-1) - 0 + 1 => N. If you want to assign B to the last element of A, you can do that by B = A[N-1], or B = A[-1], since negative indices point to elements of the list from the end. However, given you redeclare B = [0] * N, you could do away with the first assignment

这篇关于算法:IndexError:列表索引超出范围(Python)的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！