IndexError:元组索引超出范围 [英] IndexError: tuple index out of range
问题描述
我是指 django文档的此页面写入视图。有人可以解释我做错了什么吗?还有什么可以解决的问题?
I was referring to this page of django documentation to write views. Can someone explain what I did wrong ? And what could be the solution
self.object_list = self.get_queryset()
File "/vagrant/projects/kodeworms/course/views.py", line 23, in get_queryset
self.Course = get_object_or_404(Course, name=self.args[0])
IndexError: tuple index out of range
我的views.py文件
My views.py file
# Create your views here.
from django.views.generic import ListView, DetailView
from django.shortcuts import get_object_or_404
from .models import Course, Content
class PublishedCourseMixin(object):
def get_queryset(self):
queryset = super(PublishedCourseMixin, self).get_queryset()
return queryset.filter(published_course=True)
class CourseListView(PublishedCourseMixin, ListView):
model = Course
template_name = 'course/course_list.html'
class CourseContentListView(ListView):
model = Content
template_name = 'course/content_list.html'
def get_queryset(self):
self.Course = get_object_or_404(Course, name=self.args[0])
return Content.objects.filter(course=self.course, published=True)
我的urls.py文件
My urls.py file
from django.conf.urls import patterns, url
from . import views
urlpatterns = patterns('',
url(r"^$", views.CourseListView.as_view(), name="list" ),
url(r"^(?P<slug_topic_name>[\w-]+)/$", views.CourseContentListView.as_view(), name="list"),
)
推荐答案
您正在使用 self.args [0]
这是位置参数,但是你传递一个关键字参数到你的视图。
You are using self.args[0]
which is for positional arguments, but you are passing in a keyword argument to your view.
由于你没有位置参数 self.args
是一个零长度的元组,这就是为什么你得到这个例外。
As you have no positional arguments self.args
is a zero-length tuple which is why you get that exception.
你应该使用 self.kwargs [ 'slug_topic_name']
因为你的url中有一个关键字参数。
You should be using self.kwargs['slug_topic_name']
since you have a keyword argument in your url.
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