aws cloudformation 错误:无法解压缩上传的文件.请检查您的文件，然后再次尝试上传 [英] aws cloudformation error: Could not unzip uploaded file. Please check your file, then try to upload again

问题描述

使用 aws cloudformation 命令 package 和 deploy 我试图将我的本地 lambda 函数复制到 s3 并部署模板.但是我在部署堆栈时遇到了一个问题.出现错误:无法解压缩上传的文件.请检查您的文件，然后再次尝试上传.(服务:AWSLambdaInternal；状态代码:400

Using aws cloudformation commands package and deploy I'm trying to copy my local lambda function to s3 and deploy template. But I have faced with a problem during deploying a stack. An error occur: Could not unzip uploaded file. Please check your file, then try to upload again. (Service: AWSLambdaInternal; Status Code: 400

问题:当我手动压缩 labmda 函数并将其复制到 s3 时 - 它可以工作.我的工作流程或模板有什么问题?

Question: When I zip the labmda function manually and copy it to s3 - it works. What wrong in my workflow or my template?

我的代码结构:

./template/template.yaml

./template/lambda.py

命令:

aws cloudformation package \
--template-file ./template.yaml \
--output-template-file ./output-template2.yaml \
--s3-bucket "vmv-template-2"

aws cloudformation deploy \
--template-file ./output-template2.yaml \
--stack-name audi2 \
--capabilities CAPABILITY_IAM

我的模板文件

AWSTemplateFormatVersion: '2010-09-09'
Parameters:
  lambdaFunctionName:
    Type: "String"
    AllowedPattern: "^[a-zA-Z0-9]+[a-zA-Z0-9-]+[a-zA-Z0-9]+$"
    Default: "createS3Object"
Resources:
  LambdaCreateS3Object:
    Type: 'AWS::Lambda::Function'
    Properties:
      Description: Create s3 object and write content from request body
      FunctionName: !Ref "lambdaFunctionName"
      Code: ./lambda.py
      Timeout: 60
      Handler: lambda.lambda_handler
      Runtime: python3.7
      MemorySize: 128
      Role: !GetAtt LambdaExecutionRole.Arn
  LambdaExecutionRole:
    Type: "AWS::IAM::Role"
    Properties:
      AssumeRolePolicyDocument:
        Version: "2012-10-17"
        Statement:
          - Action:
              - "sts:AssumeRole"
            Effect: "Allow"
            Principal:
              Service:
                - "lambda.amazonaws.com"
      Policies:
        - PolicyDocument:
            Version: "2012-10-17"
            Statement:
              - Action:
                  - "logs:CreateLogGroup"
                  - "logs:CreateLogStream"
                  - "logs:PutLogEvents"
                Effect: "Allow"
                Resource:
                  - !Sub "arn:aws:logs:${AWS::Region}:${AWS::AccountId}:log-group:/aws/lambda/${lambdaFunctionName}:*"
          PolicyName: "lambda"
        - PolicyName: getAndDeleteObjects
          PolicyDocument:
            Version: '2012-10-17'
            Statement:
              - Effect: Allow
                Action:
                  - 's3:GetObject'
                  - 's3:DeleteObject'
                  - 's3:PutObject'
                Resource: arn:aws:s3:::*
  lambdaLogGroup:
    Type: "AWS::Logs::LogGroup"
    Properties:
      LogGroupName: !Sub "/aws/lambda/${lambdaFunctionName}"
      RetentionInDays: 90

推荐答案

基于评论.

我试图验证报告的问题.发现的是 package 命令的一个相当有趣的行为.

I tried to verify the issue reported. What was found, was a rather intresting behavior of the package command.

即当package命令以如下方式执行时(template文件夹的外部):

Namely, when the package command is executed in the following way (outside of template folder):

aws cloudformation package \
  --template-file ./template/template.yaml \
  --output-template-file ./output-template2.yaml \
  --s3-bucket "vmv-template-2"

上传到 S3 的对象只是一个重命名的 template.yaml 文件.然后 deploy 命令失败，因为报告需要一个 ZIP 文件.

The uploaded object to S3 will be just a renamed template.yaml file. Then the deploy command fails as reported expecting a ZIP file.

但是，当 package 命令在 inside template 文件夹中执行时，它会按预期工作，在 S3 中生成一个 ZIP:

However, when the package command is executed inside template folder, then it works as expected, producing a ZIP in S3:

aws cloudformation package \
  --template-file ./template.yaml \
  --output-template-file ./output-template2.yaml \
  --s3-bucket "vmv-template-2"

之后，deploy 命令成功.

这篇关于aws cloudformation 错误:无法解压缩上传的文件.请检查您的文件，然后再次尝试上传的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！