Ansible 从变量中替换多行 [英] Ansible replace multiple lines from variable

问题描述

我有以下 Ansible 变量:

I have the following Ansible variable:

test_entries:
    "
    test-auth-ip=192.168.1.22
    test-auth-serv=example1.com
    test-auth-net=192.168.1.254
    test-auth-blabla=test123 
    "

我还有一个包含以下几行的文本文件:

I also have a text file which contains the following lines:

   test-auth-str1=null
   test-auth-str2=null
   test-auth-serv=null
   test-auth-net=0.0.0.0
   test-auth-str3=null
   test-auth-str4=null

我希望能够替换文件中与变量中的行匹配的任何行，直到="符号.(正则表达式:^test-auth(.*?=))

I would like to be able to replace any line from the file which matches line from the variable until the "=" sign. (regex: ^test-auth(.*?=))

我阅读了 Ansible 文档.用于lineinfile"和替换"功能.然而，我找不到如何用正则表达式逐行匹配.

I read the Ansible doc. for "lineinfile" and "replace" functionalities. However, I couldn't find how to match line by line with regex.

预期结果

 test-auth-str1=null
 test-auth-str2=null
 test-auth-serv=example1.com
 test-auth-net=192.168.1.254
 test-auth-str3=null
 test-auth-str4=null

推荐答案

尝试

test_entries:
 test-auth-ip     : 192.168.1.22
 test-auth-serv   : example1.com
 test-auth-net    : 192.168.1.254
 test-auth-blabla : test123

然后在你的任务中 -

- replace:
    path: /your/file
    regexp: '^{{ item.key }}=.*$'
    replace: '{{ item.key }}={{ item.value }}'
  with_dict: "{{ test_entries }}"

我也经常使用匿名字典数组，以及我命名的属性，而不是key 和value.主要区别在于它可以让您控制顺序(这在这里似乎无关紧要)并跳过 key &value 关键字.

I also often use an array of anonymous dictionaries, and whatever I named the attributes instead of key and value. The major differences are that it lets you control order (which doesn't seem to matter here) and skip the key & value keywords.

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