如何使用正则表达式禁止连续的五位数和更多位数? [英] How to disallow consecutive five digits and more using regex?

问题描述

如果字符串包含连续的五位数字，我想禁止:12345、11111、123456.

I would like to disallow if the string contains consecutive five digits and more like: 12345, 11111, 123456.

我已成功使用以下正则表达式禁止字符串中的任何数字:

I have got success in disallowing any number in string using following regex:

/^[^0-9]+$/

我创建了一个沙盒演示.我想禁止五个连续的数字/数字.目前它不允许任何号码.

I have created a sandbox demo. I want to disallow five consecutive numbers/digits. Currently it is disallowing any number.

推荐答案

匹配5个连续数字的正则表达式为\d{5}.

The regex matching 5 consecutive digits is \d{5}.

要禁止这样的字符串(实际上，甚至更多的连续数字)，在源字符串中的任何位置，应放置此正则表达式:

To disallow such a string (actually, even more consecutive digits), at any position in the source string, this regex should be put:

• 在否定查找中:(?!...),
• 在匹配任意数量(零个或多个)任何字符的正则表达式之后 .*?(不情愿的变体).

• inside a negative lookup: (?!...),
• after a regex matching any number (zero or more) of any chars .*? (reluctant variant).

在这个否定查找之后，应该有一个匹配整个字符串的正则表达式:.+ (我假设你对空字符串不感兴趣，所以我把+，不是 *).

After this negative lookup, there should be a regex matching the whole string: .+ (I assume that you are not interested in an empty string, so I put +, not *).

上面的整个正则表达式应该以 ^ 开头，然后是 $ 锚点.

The whole regex above should be preceded with ^ and followed with $ anchors.

所以整个正则表达式可以是:^(?!.*?\d{5}).+$

So the whole regex can be: ^(?!.*?\d{5}).+$

这篇关于如何使用正则表达式禁止连续的五位数和更多位数?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！