如何从xml中获取节点而不知道它在flex中的级别? [英] How to get a node from xml not knowing its level in flex?

问题描述

我的问题是，如何在要插入的女巫中获取节点:

My question is, that how can I get the node in witch I want to insert:

即

    <folder id="1">
          <folder id="4">
               <folder id="5"></folder>
          </folder>
    </folder>
    <folder id="2">
          <file id="4"/>
    </folder>
    <folder id="3">
    </folder>

我想获取 id = 4 的文件夹，但这可以在任何级别.

I want to get folder with id = 4, but that can be on any level.

如果文件夹不能相互包含，那就是这样 myNode = xml.folder.(@id == 4).

If folders couldn't contain one another than it would be like this myNode = xml.folder.(@id == 4).

推荐答案

使用 .. 运算符，它会查找所有具有给定名称的节点，无论它们有多深.例如 xml..folder将在您的 XML 中找到所有 节点.所以你要做的是 myNode = xml..folder.(@id == 4).

Use the .. operator, it looks for all the nodes with given name and it doesn't matter how deep they are. For example xml..folder will find all the <folder/> nodes in your XML. So what you're trying to do will be myNode = xml..folder.(@id == 4).

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