如何从XML不知道它在柔性水平的一个节点？ [英] How to get a node from xml not knowing its level in flex?

问题描述

我的问题是，我怎么能得到该节点在女巫我要插入：

My question is, that how can I get the node in witch I want to insert:

即

    <folder id="1">
          <folder id="4">
               <folder id="5"></folder>
          </folder>
    </folder>
    <folder id="2">
          <file id="4"/>
    </folder>
    <folder id="3">
    </folder>

我想获得的文件夹id为4，但可以在任何水平。

I want to get folder with id = 4, but that can be on any level.

如果文件夹不能包含另一个比它会是这样MYNODE = xml.folder。（@ ID = = 4）。

If folders couldn't contain one another than it would be like this myNode = xml.folder.(@id == 4).

推荐答案

使用了 .. 运营商，它看起来对所有与给定名称的节点，它不不管有多深他们。例如 xml..folder 会发现所有的＆LT;文件夹/＆GT; 在XML节点。所以，你现在要做的将是什么 MYNODE = xml..folder。（@ ID = = 4）。

Use the .. operator, it looks for all the nodes with given name and it doesn't matter how deep they are. For example xml..folder will find all the <folder/> nodes in your XML. So what you're trying to do will be myNode = xml..folder.(@id == 4).

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