替换 Spark 数据框中列名的特殊字符 [英] Replace Special characters of column names in Spark dataframe

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本文介绍了替换 Spark 数据框中列名的特殊字符的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我将输入 spark-dataframe 命名为 df 作为,

I have my input spark-dataframe named df as,

+---------------+----------------+-----------------------+
|Main_CustomerID|126+ Concentrate|2.5 Ethylhexyl_Acrylate|
+---------------+----------------+-----------------------+
|         725153|             3.0|                    2.0|
|         873008|             4.0|                    1.0|
|         625109|             1.0|                    0.0|
+---------------+----------------+-----------------------+

我需要从 df 的列名中删除特殊字符,如下所示,

I need to remove the special characters from the column names of df like following,

  • 删除+

将空格替换为下划线

所以我的 df 应该像

+---------------+---------------+-----------------------+
|Main_CustomerID|126_Concentrate|2_5_Ethylhexyl_Acrylate|
+---------------+---------------+-----------------------+
|         725153|            3.0|                    2.0|
|         873008|            4.0|                    1.0|
|         625109|            1.0|                    0.0|
+---------------+---------------+-----------------------+

使用 Scala,我通过以下方式实现了这一点

Using Scala, I have achieved this by,

var tableWithColumnsRenamed = df

for (field <- tableWithColumnsRenamed.columns) {
      tableWithColumnsRenamed = tableWithColumnsRenamed
        .withColumnRenamed(field, field.replaceAll("\\.", "_"))
    }
for (field <- tableWithColumnsRenamed.columns) {
      tableWithColumnsRenamed = tableWithColumnsRenamed
        .withColumnRenamed(field, field.replaceAll("\\+", ""))
    }
for (field <- tableWithColumnsRenamed.columns) {
      tableWithColumnsRenamed = tableWithColumnsRenamed
        .withColumnRenamed(field, field.replaceAll(" ", "_"))
    }

df = tableWithColumnsRenamed

当我使用时,

for (field <- tableWithColumnsRenamed.columns) {
      tableWithColumnsRenamed = tableWithColumnsRenamed
        .withColumnRenamed(field, field.replaceAll("\\.", "_"))
    .withColumnRenamed(field, field.replaceAll("\\+", ""))
    .withColumnRenamed(field, field.replaceAll(" ", "_"))
    }

我得到的第一个列名是 126 Concentrate 而不是 126_Concentrate

I got the first column name as 126 Concentrate instead of getting 126_Concentrate

但我不喜欢 3 for 循环来替换这个.我能得到解决方案吗?

But I don't prefer 3 for loops for this replacement. Can I get the solution?

推荐答案

df
  .columns
  .foldLeft(df){(newdf, colname) =>
    newdf.withColumnRenamed(colname, colname.replace(" ", "_").replace(".", "_"))
  }
  .show

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