spark数据框:爆炸列表列 [英] spark dataframe: explode list column

问题描述

我有一个来自 Spark Aggregator 的输出，它是 List[Character]

case class Character(name: String, secondName: String,faculty: String)val charColumn = HPAggregator.toColumnval resultDF = someDF.select(charColumn)

所以我的数据框看起来像:

+-----------------------------------------------+|价值 |+-----------------------------------------------+|[[哈利，波特，格兰芬多]，[罗恩，韦斯莱...|+-----------------------------------------------+

现在我想把它转换成

+-----------------------------------+|姓名 |第二个名字|教师|+---------------------------------+|哈利|波特|格兰芬多||罗恩 |韦斯莱|格兰芬多|

我怎样才能正确地做到这一点?

解决方案

这可以使用 Explode 和 Split Dataframe 函数来完成.

下面是一个例子:

<预><代码>>>>df = spark.createDataFrame([[[['a','b','c'], ['d','e','f'], ['g','h','i']]]],["col1"])>>>df.show(20, 假)+----------------------------------------------------------------------+|col1 |+----------------------------------------------------------------------+|[WrappedArray(a, b, c), WrappedArray(d, e, f), WrappedArray(g, h, i)]|+----------------------------------------------------------------------+>>>从 pyspark.sql.functions 导入爆炸>>>out_df = df.withColumn("col2",explode(df.col1)).drop('col1')>>>>>>out_df .show()+---------+|列2|+---------+|[a, b, c]||[d, e, f]||[g, h, i]|+---------+>>>out_df.select(out_df.col2[0].alias('c1'), out_df.col2[1].alias('c2'), out_df.col2[2].alias('c3')).show()+---+---+---+|c1|c2|c3|+---+---+---+|一个|乙|| ||d|e|f||克|高|我|+---+---+---+>>>

I've got an output from Spark Aggregator which is List[Character]

case class Character(name: String, secondName: String, faculty: String)
val charColumn = HPAggregator.toColumn
val resultDF = someDF.select(charColumn)

So my dataframe looks like:

+-----------------------------------------------+
|               value                           |
+-----------------------------------------------+
|[[harry, potter, gryffindor],[ron, weasley ... |
+-----------------------------------------------+

Now I want to convert it to

+----------------------------------+
| name  | second_name | faculty    |
+----------------------------------+
| harry | potter      | gryffindor |
| ron   | weasley     | gryffindor |

How can I do that properly?

解决方案

This can be done using Explode and Split Dataframe functions.

Below is an example:

>>> df = spark.createDataFrame([[[['a','b','c'], ['d','e','f'], ['g','h','i']]]],["col1"])
>>> df.show(20, False)
+---------------------------------------------------------------------+
|col1                                                                 |
+---------------------------------------------------------------------+
|[WrappedArray(a, b, c), WrappedArray(d, e, f), WrappedArray(g, h, i)]|
+---------------------------------------------------------------------+

>>> from pyspark.sql.functions import explode
>>> out_df = df.withColumn("col2", explode(df.col1)).drop('col1')
>>>
>>> out_df .show()
+---------+
|     col2|
+---------+
|[a, b, c]|
|[d, e, f]|
|[g, h, i]|
+---------+

>>> out_df.select(out_df.col2[0].alias('c1'), out_df.col2[1].alias('c2'), out_df.col2[2].alias('c3')).show()
+---+---+---+
| c1| c2| c3|
+---+---+---+
|  a|  b|  c|
|  d|  e|  f|
|  g|  h|  i|
+---+---+---+

>>>

这篇关于spark数据框:爆炸列表列的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！