Django Rest Api - ManyToManyField,在练习数组中显示“标题"而不是“id" [英] Django Rest Api - ManyToManyField, Display 'title' instead of 'id' in the Exercises Array
问题描述
Django Rest Api - ManyToManyField,在练习数组中显示title"而不是id"
HTTP 200 OK允许:获取、发布、放置、删除、补丁内容类型:应用程序/json变化:接受[{身份证":1,"title": "推动锻炼 Bjarred","description": "Kör Hårt!",练习":[3、4、5、6、9、10],有氧运动": [4]},{身份证":2,"title": "拉力训练 Loddekopinge",描述": "",练习":[1、2、7、8],有氧运动": []},{身份证":3,"title": "CardioPass",描述": "",练习":[],有氧运动": [2、3、4]}]
Serializer(所以我想显示标题而不是每个练习的id)
class WorkoutSerializer(serializers.ModelSerializer):元类:模型 = 锻炼fields = ('id', 'title', 'description', 'exercises', 'cardio')
这里是模型,注意我想在api数组中显示每个练习的练习名称,我不要id!- 马上就过去了!:)
class Bodypart(models.Model):name = models.CharField(max_length=100)def __str__(self):返回 self.name类练习(模型.模型):name = models.CharField(max_length=40)bodyparts = models.ManyToManyField(Bodypart, blank=True)def __str__(self):返回 self.name类有氧(模型.模型):name = models.CharField(max_length=40)时间 = 模型.IntegerField(默认 = 10)def __str__(self):返回 self.name元类:verbose_name_plural = 'cardio'类锻炼(模型.模型):标题=models.CharField(max_length=120)description = models.CharField(max_length=1000, blank=True)练习=models.ManyToManyField(练习,空白=真)心=models.ManyToManyField(心,空白=真)def __str__(self):返回 self.title
你可以通过像这样改变你的 WorkoutSerializer
来获得这个
class WorkoutSerializer(serializers.ModelSerializer):练习 = serializers.StringRelatedField(many=True, read_only=True)元类:字段 = ('id', 'title', 'description', 'exercises', 'cardio', )
你会得到这样的结果json
<预><代码>[{身份证":1,"title": "推动锻炼 Bjarred","description": "Kör Hårt!",练习":[练习1",练习2",练习4",练习3"],有氧运动": [4]},...有关 django rest 序列化程序的更多信息,请参见 https://www.django-rest-framework.org/api-guide/relations/
Django Rest Api - ManyToManyField, Display 'title' instead of 'id' in the Exercises Array
HTTP 200 OK
Allow: GET, POST, PUT, DELETE, PATCH
Content-Type: application/json
Vary: Accept
[
{
"id": 1,
"title": "Push Workout Bjarred",
"description": "Kör Hårt!",
"exercises": [
3,
4,
5,
6,
9,
10
],
"cardio": [
4
]
},
{
"id": 2,
"title": "Pull Workout Loddekopinge",
"description": "",
"exercises": [
1,
2,
7,
8
],
"cardio": []
},
{
"id": 3,
"title": "CardioPass",
"description": "",
"exercises": [],
"cardio": [
2,
3,
4
]
}
]
Serializer (So I want to display the title and not the id for every exercise)
class WorkoutSerializer(serializers.ModelSerializer):
class Meta:
model = Workout
fields = ('id', 'title', 'description', 'exercises', 'cardio')
Here are the models, note that I want to display the exercise name for every exercise in the api array, I don't want the id! - That is passed right now! :)
class Bodypart(models.Model):
name = models.CharField(max_length=100)
def __str__(self):
return self.name
class Exercise(models.Model):
name = models.CharField(max_length=40)
bodyparts = models.ManyToManyField(Bodypart, blank=True)
def __str__(self):
return self.name
class Cardio(models.Model):
name = models.CharField(max_length=40)
time = models.IntegerField(default=10)
def __str__(self):
return self.name
class Meta:
verbose_name_plural = 'cardio'
class Workout(models.Model):
title = models.CharField(max_length=120)
description = models.CharField(max_length=1000, blank=True)
exercises = models.ManyToManyField(Exercise, blank=True)
cardio = models.ManyToManyField(Cardio, blank=True)
def __str__(self):
return self.title
You can get this by changing your WorkoutSerializer
like this
class WorkoutSerializer(serializers.ModelSerializer):
exercises = serializers.StringRelatedField(many=True, read_only=True)
class Meta:
fields = ('id', 'title', 'description', 'exercises', 'cardio', )
You will get the result json like this
[
{
"id": 1,
"title": "Push Workout Bjarred",
"description": "Kör Hårt!",
"exercises": [
"Exercise 1",
"Exercise 2",
"Exercise 4",
"Exercise 3"
],
"cardio": [
4
]
},
...
More about django rest serializers see https://www.django-rest-framework.org/api-guide/relations/
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