在Django 2.1中查询模型时返回ManyToManyField ID? [英] Return ManyToManyField IDs when querying model in Django 2.1?

问题描述

我有两个非常简单的模型:

I have two very simple models:

class Person(models.Model):
    full_name = models.CharField(max_length=120)

class Event(models.Model):
    event_date = models.DateField()
    short_description = models.CharField(max_length=250)
    people_involved = models.ManyToManyField(
        Person, blank=True, related_name="people_involved"
    )

我想返回所有事件，包括people_involved.

I want to return all events, including the people_involved.

在views.py中，我有以下内容:

In views.py, I have the following:

def alljson(request):
    events = Event.objects.values()
    return JsonResponse(list(events), safe=False)

这将返回:

[
    {
        "id": 9, 
        "event_date": "2019-01-01", 
        "short_description": "New Year's Party", 
    }, 
...
]

如何在此响应中包含people_involved ManyToManyField?

How do I include the people_involved ManyToManyField in this response?

推荐答案

您可以使用 model_to_dict 像这样:

from django.forms.models import model_to_dict

e_list = []
p_list = []
events = Event.objects.all()
for e in events:
    e_list.append(model_to_dict(e, fields=['event_date', 'short_description']))
    for p in e.people_involved.all():
        p_list.append(model_to_dict(p, fields=['full_name']))   
data = {'events': e_list, 'people_involved': p_list}
return JsonResponse(data)

在model_to_dict中，您可以包括或排除特定字段:)

with model_to_dict you an include or exclude a particular field if you want to :)

或

您可以像这样使用序列化器:

from django.core import serializers 

data = {}
events = Event.objects.all()
s_events = serializers.serialize("json", events)
data['events'] = s_events
for event in events:
    data['persons'] = serializers.serialize("json", event.people_involved.all())
return JsonResponse(data)

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