Discord.js 通过 feed-watcher 进行媒体集成，无法从更新中获取 feed 链接 [英] Discord.js medium integration via feed-watcher, can't get feed link from the update

问题描述

我正在尝试构建媒体集成，因此当我的新帖子到达媒体时，机器人会将帖子链接发送到不和谐频道.问题是我不知道如何从提要响应中获取数据，所以我可以在消息中使用它.收到来自提要的响应后，它看起来像这样.

I'm trying to build medium integration so when i new post arrives on medium, bot will then send the post link to the discord channel. The Problem is i don't know how to take data from the feed response so i can use it in the message. Once i receive the response from the feed, it looks like this.

    title: 'Hopefully will be done soon',
    description: '<p>Still making final testing!</p><img src="https://medium.com/_/stat?event=post.clientViewed&referrerSource=full_rss&postId=3d067e89b091" width="1" height="1" alt="">',
    summary: null,
    date: 2021-09-12T01:26:33.000Z,
    pubdate: 2021-09-12T01:26:33.000Z,
    pubDate: 2021-09-12T01:26:33.000Z,
    link: 'https://rasmont.medium.com/hopefully-will-be-done-soon-3d067e89b091?source=rss-762047c9bd39------2',
    guid: 'https://medium.com/p/3d067e89b091',
    author: 'RasmonT',
    comments: null,
    origlink: null,
    image: {},
    source: {},
    categories: [],
    enclosures: [],
    'rss:@': {},
    'rss:title': { '@': {}, '#': 'Hopefully will be done soon' },
    'rss:link': {
      '@': {},
      '#': 'https://rasmont.medium.com/hopefully-will-be-done-soon-3d067e89b091?source=rss-762047c9bd39------2'
    },
    'rss:guid': { '@': [Object], '#': 'https://medium.com/p/3d067e89b091' },
    'dc:creator': { '@': {}, '#': 'RasmonT' },
    'rss:pubdate': { '@': {}, '#': 'Sun, 12 Sep 2021 01:26:33 GMT' },
    'atom:updated': { '@': {}, '#': '2021-09-12T01:26:33.080Z' },
    'content:encoded': {
      '@': {},
      '#': '<p>Still making final testing!</p><img src="https://medium.com/_/stat?event=post.clientViewed&referrerSource=full_rss&postId=3d067e89b091" width="1" height="1" alt="">'
    },
    meta: {
      '#ns': [Array],
      '@': [Array],
      '#xml': [Object],
      '#type': 'rss',
      '#version': '2.0',
      title: 'Stories by RasmonT on Medium',
      description: 'Stories by RasmonT on Medium',
      date: 2021-09-12T01:39:23.000Z,
      pubdate: 2021-09-12T01:39:23.000Z,
      pubDate: 2021-09-12T01:39:23.000Z,
      link: 'https://medium.com/@rasmont?source=rss-762047c9bd39------2',
      xmlurl: 'https://medium.com/@rasmont/feed',
      xmlUrl: 'https://medium.com/@rasmont/feed',
      author: '[e-mail]',
      language: null,
      favicon: null,
      copyright: null,
      generator: 'Medium',
      cloud: [Object],
      image: [Object],
      categories: [],
      'rss:@': {},
      'rss:title': [Object],
      'rss:description': [Object],
      'rss:link': [Object],
      'rss:image': [Object],
      'rss:generator': [Object],
      'rss:lastbuilddate': [Object],
      'atom:link': [Array],
      'rss:webmaster': [Object]
    }
  },

我试图解析响应，所以我可以从这样的响应中获取链接.

I tried to parse response so i can take the link from the response like this.

const link = JSON.parse(entry) console.log('FEED Call response:', link[link"]);

client.on('ready', () => {
  watcher.on('new entries', function (entries) {
    entries.forEach(function (entry) {
      const link = JSON.parse(entry)
      console.log('FEED Call response:', link["link"]);
      console.log(entry)
    })
  })
  watcher
  .start()
  .then(function (entries) {
    console.log(entries)
  })
  .catch(function(error) {
    console.error(error)
  })
})

知道如何从响应中接收我想要的数据以便我可以在消息中使用它吗?

Any idea how can I receive the data I want from the response so I can use it in the message?

错误:SyntaxError:JSON 中位置 1 的意外标记 o

更新:我尝试使用它，但我不知道如何从响应中获取链接.

Updated: I tried to use this, however i don't know how to get the link from the response.

    const link = JSON.stringify(entries)
    console.log('FEED Call response:', link);
    console.log(`Link:`, link[0].link)

回复是链接:[功能:链接]

推荐答案

您根本不必使用 JSON.parse！接收到的数据已经是你想要的对象了.JSON.parse 自动将它的第一个参数设置为字符串，并使其更改为以下字符串:

You do not have to use JSON.parse at all! The received data is already the object you want. JSON.parse automatically sets its first argument as a string, and that makes it change to the following string:

"[object Object]"

JSON 允许 [ 但不允许不带引号的 o.以下代码可以正常工作.

JSON allows the [ but not the o without a quotation mark. The following code will work just fine.

entries.forEach((entry) => {
      console.log('FEED Call response:', entry);
      console.log(entry[0].link)
})

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