在 Appium (Android) 中获取所有子笔记仅比父对象低一级 [英] Get all child notes only one level lower from parent object in Appium (Android)

问题描述

我编写了一个自动化测试软件，现在遇到一个问题.在我实际的原生应用中，我有一个像这样的 ListView:

I write an automation testing software and have one problem now. In my actual native app I have a ListView like this here:

• 列表视图
  • 线性布局
    • 线性布局
      • 线性布局
      • 线性布局
      • 线性布局

      ...等等.

      我需要和想要的是从 ListView 中降低所有一层 LinearLayout(迭代的，可见和不可见元素):

      What I need and want is to get all one level lower LinearLayout (iterative ones, visible and non visible elements) from ListView:

      ListView : {LinearLayout, LinearLayout, ...}

      ListView : {LinearLayout, LinearLayout, ...}

      使用该代码，我可以从 ListView 中获取所有子项，但对我来说太多了:

      With that code I get all childs from ListView, but its to much for me:

      listViewChildElements       = "[...]android.widget.ListView[1]//android.widget.LinearLayout";
      app.getDriver().findElements(By.xpath(listViewChildElements));
      

      在另一篇文章中，我看到一些带有计数"的内容，但我不明白.

      In another post I see something with 'count', but I don't understand it.

      感谢您的帮助，很高兴认识您.

      Thanks for your help and nice to meet you.

      在@har07 的帮助下，我编写了一个函数，不是最好的或最好的解决方案，也不是最终的，而是正确的第一步:

      With the help of @har07 I write one function, not best or finest solution and not finally, but the 1st step in the right lane:

          public static List<String> getAllViewElements(App app){
          int i = 0;
      
          List<String> writtenElementsByText = new ArrayList<String>();
      
          while(true){
              if(!writtenElementsByText.isEmpty()){
                  String recentLastItem = writtenElementsByText.get(writtenElementsByText.size()-1);
                  if(recentLastItem.equals("Alle Themen"))
                      break;
                  else
                      app.getDriver().scrollTo(recentLastItem);
              }
      
              List<WebElement> tmp = app.getDriver().findElements(By.xpath(listViewChildElements));
      
      
              if(writtenElementsByText.isEmpty())
                  for(WebElement e: tmp){
                      writtenElementsByText.add(getTextFromElement(e));
                  }
              else
                  for(WebElement e: tmp){
                      String activualElemenByText = getTextFromElement(e);
                      if(!writtenElementsByText.contains(activualElemenByText))
                          writtenElementsByText.add(activualElemenByText);
                  }
          }
      
          System.out.println(writtenElementsByText.size());
          for(String e: writtenElementsByText){
              System.out.println("\t-\t"+e);
          }
          return writtenElementsByText;
      }
      
      public static String getTextFromElement(WebElement element){
          return element.findElement(By.id(listViewChildElementTextID)).getText();
      }
      

      推荐答案

      如果我理解正确的话，你想使用单斜杠 (/) 而不是双斜杠来从一个父元素:

      If I understand the problem correctly, you want to use single slash (/) instead of double to get direct child element from a parent element :

      listViewChildElements = "[...]android.widget.ListView[1]/android.widget.LinearLayout";
                                                              ^
                                                              notice that only one slash being 
                                                              used above
      

      有了这个改变，XPath 现在应该返回 LinearLayout，它是 ListView[1] 的直接子元素.

      With that change, the XPath should now return LinearLayout that is direct child of the ListView[1].

      这篇关于在 Appium (Android) 中获取所有子笔记仅比父对象低一级的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！