SWIFT - BLE 通信 [英] SWIFT - BLE communications
问题描述
我有一个 SWIFT 应用程序，它必须通过蓝牙低功耗模块向我的 Arduino 发送一个值！
I've got a SWIFT application that have to send a value to my Arduino with Bluetooth LowEnergy module!
我已经正确完成了搜索和连接部分，但我无法发送和接收任何数据.
I've done correctly the search and connection parts but I'm not able to send and receive any data.
这是我的代码，用于获取可用的 BLE 设备列表并将所有这些放在表格视图中，然后在应用程序提供的单元格中单击以将设备与它们连接！
Here is my code to get a list of BLE devices available and put all this in a table view then after click in a cell the app provide to connect the device with them!
所有这些都完美无缺，但我不知道将例如a"字符从应用程序发送到 BLE，然后将答案从 arduino 返回到应用程序！
All this works perfectly but I don't know to send for example a "a" character from app to BLE and get back the answer from arduino to app!
import UIKit
import CoreBluetooth
class BluetoothList: UITableViewController,CBCentralManagerDelegate, CBPeripheralDelegate {
var listValue = [Lista]()
var Blue: CBCentralManager!
var conn: CBPeripheral!
var a: String!
var char: CBCharacteristic!
func centralManager(central: CBCentralManager, didDiscoverPeripheral peripheral: CBPeripheral, advertisementData: [String : AnyObject], RSSI: NSNumber) {
if (peripheral.name == a){
self.conn = peripheral
self.conn.delegate = self
Blue.stopScan()
Blue.connectPeripheral(self.conn, options: nil)
self.performSegueWithIdentifier("ConnectionSegue", sender: nil)
}
else{
listValue = [
Lista(Name: peripheral.name!, RSS: RSSI.stringValue)
]
self.tableView.reloadData()
}
}
func centralManager(central: CBCentralManager, didConnectPeripheral peripheral: CBPeripheral) {
peripheral.delegate = self
peripheral.discoverServices(nil)
}
func peripheral(peripheral: CBPeripheral, didDiscoverServices error: NSError?) {
if let servicePeripheral = peripheral.services! as [CBService]!{
for service in servicePeripheral{
peripheral.discoverCharacteristics(nil, forService: service)
}
}
}
func peripheral(peripheral: CBPeripheral, didDiscoverCharacteristicsForService service: CBService, error: NSError?) {
if let characterArray = service.characteristics! as [CBCharacteristic]!{
for cc in characterArray {
if(cc.UUID.UUIDString == "FF05"){
print("OKOK")
peripheral.readValueForCharacteristic(cc)
}
}
}
}
func peripheral(peripheral: CBPeripheral, didUpdateValueForCharacteristic characteristic: CBCharacteristic, error: NSError?) {
if (characteristic.UUID.UUIDString == "FF05"){
let value = UnsafePointer<Int>((characteristic.value?.bytes.memory)!)
print("\(value)")
}
}
func centralManagerDidUpdateState(central: CBCentralManager){
switch(central.state){
case .PoweredOn:
Blue.scanForPeripheralsWithServices(nil, options:nil)
print("Bluetooth is powered ON")
case .PoweredOff:
print("Bluetooth is powered OFF")
case .Resetting:
print("Bluetooth is resetting")
case .Unauthorized:
print("Bluetooth is unauthorized")
case .Unknown:
print("Bluetooth is unknown")
case .Unsupported:
print("Bluetooth is not supported")
}
}
override func viewDidLoad() {
super.viewDidLoad()
Blue = CBCentralManager(delegate: self, queue: nil)
}
override func tableView(tableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {
let currentCell = tableView.cellForRowAtIndexPath(tableView.indexPathForSelectedRow!)! as UITableViewCell
a = currentCell.textLabel?.text
Blue = CBCentralManager(delegate: self, queue: nil)
}
override func numberOfSectionsInTableView(tableView: UITableView) -> Int {
return 1
}
@IBAction func Reload_BTN(sender: AnyObject) {
self.tableView.reloadData()
}
override func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return self.listValue.count
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
}
override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
let cella = self.tableView.dequeueReusableCellWithIdentifier("Cella", forIndexPath: indexPath)
let Lista = self.listValue[indexPath.row]
cella.textLabel?.text = Lista.Name
cella.accessoryType = UITableViewCellAccessoryType.DisclosureIndicator
return cella
}
推荐答案
以下代码适用于 Swift 3 (XCode 8 Beta 6).这是将标准 UUID 用于串行端口的示例，例如某些商业模块上的串行端口.因此，服务和特性的声明应如下所示:
The following code is for Swift 3 (XCode 8 Beta 6). It's an example using the standard UUIDs for serial ports like the ones on some commercial modules. So the declarations for the service and characteristics should look like this:
private let UuidSerialService = "6E400001-B5A3-F393-E0A9-E50E24DCCA9E"
private let UuidTx = "6E400002-B5A3-F393-E0A9-E50E24DCCA9E"
private let UuidRx = "6E400003-B5A3-F393-E0A9-E50E24DCCA9E"
然后你的委托的 didDiscoverCharacteristic 方法可以是这样的:
And then your delegate's method for the didDiscoverCharacteristic can be something like this:
public func peripheral(_ peripheral: CBPeripheral, didDiscoverCharacteristicsFor service: CBService, error: Error?)
{
if let characteristics = service.characteristics {
for characteristic in characteristics {
// Tx:
if characteristic.uuid == CBUUID(string: UuidTx) {
print("Tx char found: \(characteristic.uuid)")
txCharacteristic = characteristic
}
// Rx:
if characteristic.uuid == CBUUID(string: UuidRx) {
rxCharacteristic = characteristic
if let rxCharacteristic = rxCharacteristic {
print("Rx char found: \(characteristic.uuid)")
serialPortPeripheral?.setNotifyValue(true, for: rxCharacteristic)
}
}
}
}
}
对于写入 Tx，类似于以下的工作，其中 value 是 [UInt8]:
For writing to the Tx, something like the following works, where value is an [UInt8]:
let data = NSData(bytes: value, length: value.count)
serialPortPeripheral?.writeValue(data as Data, for: txCharacteristic, type: CBCharacteristicWriteType.withResponse)
阅读?
public func peripheral(_ peripheral: CBPeripheral, didUpdateValueFor characteristic: CBCharacteristic, error: Error?) {
let rxData = characteristic.value
if let rxData = rxData {
let numberOfBytes = rxData.count
var rxByteArray = [UInt8](repeating: 0, count: numberOfBytes)
(rxData as NSData).getBytes(&rxByteArray, length: numberOfBytes)
print(rxByteArray)
}
}
最后，如果您不知道或不确定您的 BLE 设备的服务和特性，您可以寻找一款名为LightBlue"的免费 iOS 应用.它将发现一个设备，如果您连接到它，它将列出所有服务和特征.请注意，当 LightBlue 连接到您的设备时，您的应用显然无法访问 BLE 硬件.
Finally, if you don't know or you are not sure about the services and characteristics of your BLE device, you can look for a free iOS app called "LightBlue". It will discover a device and if you connect to it, it will list all services and characteristics. Just be aware that obvoiusly your app will not be able to access the BLE hardware while LightBlue is connected to your device.
这篇关于SWIFT - BLE 通信的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
