将变量从c程序传递给shell脚本作为参数 [英] Passing variable from c program to shell script as argument

问题描述

我正在从c"程序调用 shell 脚本，并且在 c 中有一些变量，我想将它们作为参数传递给 shell 脚本.我尝试使用 system() 来调用 shell 脚本，但我作为参数传递的变量被视为字符串而不是变量.

I am calling a shell script from a 'c' program and have some variables in c which I would like to pass as arguments to the shell script. I tried using the system() to call the shell script but the variable I pass as argument is considered as a string rather than a variable.

推荐答案

shell script (a.sh):

shell script (a.sh):

# iterates over argument list and prints
for (( i=1;$i<=$#;i=$i+1 ))
do
     echo ${!i}  
done

C 代码:

#include <stdio.h>

int main() { 
  char arr[] = {'a', 'b', 'c', 'd', 'e'}; 
  char cmd[1024] = {0}; // change this for more length
  char *base = "bash a.sh "; // note trailine ' ' (space) 
  sprintf(cmd, "%s", base);
  int i;
  for (i=0;i<sizeof(arr)/sizeof(arr[0]);i++) {
    sprintf(cmd, "%s%c ", cmd, arr[i]); 
  }
  system(cmd);
}

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