R中的顺序函数:参数长度不同 [英] Order function in R: argument lengths differ

问题描述

我在 R 中遇到以下错误:

I'm getting the following error in R:

argument lengths differ.

我有一个数据集，我想在两列上排序，首先是 caseID，然后是包含时间戳的列.我使用以下代码:

I have a data set I would like to order on two columns, first on caseID, then on a column that contains a timestamp. I use the following code:

mydata <- mydata[order(mydata[ ,col1], mydata[ ,col2], decreasing = FALSE),]

Col1 和 col2 是两个保存整数的变量.我查看了类似的问题并尝试了那里提出的解决方案，但没有任何效果;)

Col1 and col2 are two variables holding an integer. I have looked at similar questions and tried the solutions that were proposed there, but nothing worked ;).

有人可以帮我吗?

亲切的问候

推荐答案

R 认为你 2 列有不同的长度，有时当你不小心访问一个不存在的列时会发生这种情况，检查 col1<的值/code> 和 col2 以确保它们是适当的数字.还要查看 length(mydata[,col1]) 和 length(mydata[,col2]) 以查看这两个值是否匹配.还要检查是否缺少 、 或其他标点符号，有时如果您的语法不完全正确，那么您会得到一个长度为 1 的列表，或者一个与其他向量长度不匹配的单元素向量.

R thinks that you 2 columns have different lengths, sometimes that happens when you accidentally access a column that does not exist, check the values of col1 and col2 to make sure that they are appropriate numbers. Also look at length(mydata[,col1]) and length(mydata[,col2]) to see if those 2 values match. Also check for missing , or other punctuation, sometimes if you don't have the syntax exactly right then you get a list of length 1, or a single element vector which does not match the other vector in length.

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