如何计算ArrayList中的重复元素? [英] How to count duplicate elements in ArrayList?

问题描述

我需要分离并统计arraylist中有多少个值是相同的，并根据出现的次数打印出来.

I need to separate and count how many values in arraylist are the same and print them according to the number of occurrences.

我有一个名为 numbers 的数组列表:

I've got an arraylist called digits :

 [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765]

我创建了一个方法来分隔每个值并将其保存到一个新数组中.

I created a method which separates each value and saves it to a new array.

public static ArrayList<Integer> myNumbers(int z) {

    ArrayList<Integer> digits = new ArrayList<Integer>();
    String number = String.valueOf(z);
    for (int a = 0; a < number.length(); a++) {
        int j = Character.digit(number.charAt(a), 10);
        digits.add(j);
    }
    return digits;

}

在此之后，我得到了一个名为 numbers 的新数组.我在这个数组上使用排序

After this I've got a new array called numbers. I'm using sort on this array

Collections.sort(numbers);

我的 ArrayList 看起来像这样:

and my ArrayList looks like this:

[0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 6, 6, 6, 7, 7, 7, 7, 7, 8, 8, 8, 8, 8, 9, 9, 9]

它有:

2 times 0; 
9 times 1;
4 times 2;
6 times 3;
5 times 4;
6 times 5;
5 times 6;
5 times 7;
5 times 8;
3 times 9;

我需要打印出一串数字取决于它们有多少所以它看起来像这样:1354678290

I need to print out the string of numbers depend on how many are they So it suppose to look like this : 1354678290

推荐答案

List<String> list = new ArrayList<String>();
    list.add("a");
    list.add("b");
    list.add("c");
    list.add("a");
    list.add("a");
    list.add("a");

int countA=Collections.frequency(list, "a");
int countB=Collections.frequency(list, "b");
int countC=Collections.frequency(list, "c");

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