C#中的数组切片 [英] Array slices in C#

问题描述

你是怎么做到的?给定一个字节数组:

How do you do it? Given a byte array:

byte[] foo = new byte[4096];

如何将数组的前 x 个字节作为单独的数组获取?(具体来说，我需要它作为 IEnumerable)

How would I get the first x bytes of the array as a separate array? (Specifically, I need it as an IEnumerable<byte>)

这是为了使用 Sockets.我认为最简单的方法是数组切片，类似于 Perls 语法:

This is for working with Sockets. I figure the easiest way would be array slicing, similar to Perls syntax:

@bar = @foo[0..40];

这会将前 41 个元素返回到 @bar 数组中.C# 中是否有我遗漏的东西，或者我应该做的其他事情?

Which would return the first 41 elements into the @bar array. Is there something in C# that I'm just missing, or is there some other thing I should be doing?

LINQ 对我来说是一个选择(.NET 3.5)，如果有帮助的话.

LINQ is an option for me (.NET 3.5), if that helps any.

推荐答案

数组是可枚举的，所以你的 foo 已经是一个 IEnumerable 本身.只需使用 LINQ 序列方法，例如 Take() 得到你想要的(不要忘记在 using System.Linq; 中包含 Linq 命名空间):>

Arrays are enumerable, so your foo already is an IEnumerable<byte> itself. Simply use LINQ sequence methods like Take() to get what you want out of it (don't forget to include the Linq namespace with using System.Linq;):

byte[] foo = new byte[4096];

var bar = foo.Take(41);

如果你真的需要一个来自任何 IEnumerable 值的数组，你可以使用 ToArray() 方法.这里似乎不是这种情况.

If you really need an array from any IEnumerable<byte> value, you could use the ToArray() method for that. That does not seem to be the case here.

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