数组切片在c ++ [英] Array slicing in c++

问题描述

  
我试图将字符数组的最后4个字符切分， > char * charone =（char *）（I need the last four）
 char * chartwo = charone [-4：] 
 
 cout<另外， endl 
  

我想让这段代码返回;

  four 
  

但是c / c ++似乎

在哪里可以找到一个简单的替代方法，将一个char数组的最后4个字符返回到另一个char数组？

解决方案

尝试：

  int len = strlen charone）; 
 char * chartwo = charone +（len <4？0：len  -  4）; 
  

在C ++中，您可以用以下代替：

  char * chartwo = charone +（std :: max）（strlen（charone），4） 
  

代码使用C字符串的特殊属性，只适用于截断字符串的开头。

I am trying to slice the last 4 characters off a character array and I tried the method that python uses without success;

char *charone = (char*)("I need the last four")
char *chartwo = charone[-4:]

cout << chartwo << endl;

I would want this code to return;

four

but c/c++ doesn't seem to be that easy...

Where could I find a simple alternative that will return the last 4 chars of one char array into another char array?

解决方案

Try:

int len = strlen(charone);
char *chartwo = charone + (len < 4 ? 0 : len - 4);

In C++, you can replace that with:

char* chartwo = charone + (std::max)(strlen(charone), 4) - 4;

The code uses a special property of C strings that only works for chopping off the beginning of a string.

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