javascript从数组中的所有对象中提取某些属性 [英] javascript extract certain properties from all objects in array
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问题描述
我有一组具有相同属性的对象.每个对象都有大约一百个属性.我只想将其中的一小部分保留在新数组中:
I have an array of objects with the same properties. Each object has around a hundred properties. I want to keep only a handful of them in a new array:
var dummyArray = [{ "att1": "something", "att2": "something", ..., "att100": "something"}, { "att1": "something", "att2": "something", ..., "att100": "something"}, ...];
如何过滤/映射/减少...并提取有趣的键?
How can I filter/map/reduce... and extract the interesting keys?
const newDummArray = dummyArray.map(function(item) {
delete item.att1;
delete item.att3;
delete item.att15;
// ... (long list)
return item;
});
如何只保留每个对象的 att20
、att30
、att70
、att80
并删除其余的?
how can I keep only att20
, att30
, att70
, att80
for each object and delete the rest?
推荐答案
Use object destructuring to get the properties, and generate a new object using shorthand property names:
const dummyArray = [{ "att20": "att20", "att30": "att30", "att70": "att70", "att80": "att80"}, { "att20": "att20", "att30": "att30", "att70": "att70", "att80": "att80"}];
const result = dummyArray.map(({ att20, att30, att70, att80 }) => ({
att20,
att30,
att70,
att80
}));
console.log(result);
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