如何在Java中将字节数组转换为十六进制格式 [英] How to convert byte array to hex format in Java

问题描述

我知道您可以使用 printf 也可以使用 StringBuilder.append(String.format("%x", byte)) 将值转换为 HEX 值和在控制台上显示它们.但我希望能够实际格式化字节数组，以便每个字节都显示为十六进制而不是十进制.

I know that you can use printf and also use StringBuilder.append(String.format("%x", byte)) to convert values to HEX values and display them on the console. But I want to be able to actually format the byte array so that each byte is displayed as HEX instead of decimal.

这是我的代码的一部分，我已经做了我所说的前两种方式:

Here is a section of my code that I have already that does the first two ways that I stated:

if(bytes > 0)
    {
        byteArray = new byte[bytes]; // Set up array to receive these values.

        for(int i=0; i<bytes; i++)
        {
            byteString = hexSubString(hexString, offSet, CHARSPERBYTE, false); // Isolate digits for a single byte.
            Log.d("HEXSTRING", byteString);

            if(byteString.length() > 0)
            {
                byteArray[i] = (byte)Integer.parseInt(byteString, 16); // Parse value into binary data array.
            }
            else
            {
                System.out.println("String is empty!");
            }

            offSet += CHARSPERBYTE; // Set up for next word hex.    
        }

        StringBuilder sb = new StringBuilder();
        for(byte b : byteArray)
        {
            sb.append(String.format("%x", b));
        }

        byte subSystem = byteArray[0];
        byte highLevel = byteArray[1];
        byte lowLevel = byteArray[2];

        System.out.println("Byte array size: " + byteArray.length);
        System.out.printf("Byte 1: " + "%x", subSystem);
        System.out.printf("Byte 2: " + "%x", highLevel);
        System.out.println("Byte 3: " + lowLevel);
        System.out.println("Byte array value: " + Arrays.toString(byteArray));
        System.out.println("Byte array values as HEX: " + sb.toString());
    }
    else
    {
        byteArray = new byte[0]; // No hex data.

        //throw new HexException();
    }

    return byteArray;

被拆分成字节数组的字符串是:

The string that was split up into the byte array was:

"1E2021345A2B"

但在控制台上显示为十进制:

But displays it as decimal on the console as:

"303233529043"

有人可以帮助我如何将实际值以十六进制显示并以这种方式自然显示.提前致谢.

Could anyone please help me on how to get the actual values to be in hex and be displayed in that way naturally. Thank you in advance.

推荐答案

您可以使用 String javax.xml.bind.DatatypeConverter.printHexBinary(byte[]).例如:

You can use the String javax.xml.bind.DatatypeConverter.printHexBinary(byte[]). e.g.:

public static void main(String[] args) {
    byte[] array = new byte[] { 127, 15, 0 };
    String hex = DatatypeConverter.printHexBinary(array);
    System.out.println(hex); // prints "7F0F00"
}

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