无法修改 char* - 内存访问冲突 [英] can't modify char* - Memory access violation

问题描述

为什么显示内存访问冲突"?

Why does it say "Memory access violation"?

  char* str = "HelloGuys";
  int len = strlen(str);
  for (int i=0; i<(len/2); ++i){
        char t = str[len-i-1];
        str[len-i-1] = str[i]; //error
        str[i] = t;
  }

推荐答案

字符串文字存储在内存的只读部分.任何修改字符串文字内容的尝试都会调用未定义行为(大多数实现中的分段错误).

String literals are stored in read only section of memory. Any attempt to modify the contents of a string literal invokes Undefined Behaviour (segmentation fault on most implementations).

改为使用字符数组

char str[] = "HelloGuys";

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